将呈现的部分分配给实例变量 [英] Assign a rendered partial to an instance variable
问题描述
在 rails 4 中，我想在页面的任何地方呈现部分(比如页脚).
在 home_controller.rb 中，我在一个类中有这个:
def spree_application@test = 渲染:部分 =>'狂欢/共享/页脚'结尾当我进入索引页面并添加:
<%= @test %>什么都没发生.我知道我可以在索引页面内呈现，但我问是否有办法将呈现的链接分配给变量.
谢谢！
我在这个问题上犯了一个错误.我已经定义:spree_application
Controller 的 render 方法与视图的方法不同.您想在视图上下文中执行它:
@test = view_context.render 'spree/shared/footer'此方法与 render_to_string 的主要区别在于它返回 html_safe 字符串，因此 <%= @test %> 中的 html 标签不会被转义.
更新:
然而，这不是处理问题的正确方法.您正在寻找content_for".此方法允许您构建可在布局中使用的视图的一部分.您需要做的就是修改您的布局:
#你的应用程序布局<头>...<身体>产量:图像<div id="包装器">屈服</html>
然后在您的视图中，您可以使用
指定要显示为yield :image 的内容<% content_for :image do %><%# 这里的所有内容都将显示在包装器之外 %><%结束%>In rails 4, I want to render a partial (say the footer) on anywhere of a page.
In home_controller.rb, I have this within a class:
def spree_application
@test = render :partial => 'spree/shared/footer'
end
When I go to the index page and added:
<%= @test %>
Nothing happens. I know I can render within the index page but Im asking if there is a way to assign the rendered link to a variable.
Thanks!
Edit: I have made a mistake with this question. I have defined: spree_application
Controller's render method is different than view's one. You want to execute it in a view context:
@test = view_context.render 'spree/shared/footer'
The main difference between this method and render_to_string is that this returns html_safe string, so html tags within your <%= @test %> won't be escaped.
UPDATE:
However this is not the proper way of dealing with your problem. You are looking for 'content_for'. This method allows you to build part of the view, which can be used within the layout. All you need to do is to modify your layout:
# Your application layout
<html>
<head>
...
</head>
<body>
yield :image
<div id="wrapper">
yield
</div>
</body>
</html>
Then within your view, you can specify what is to be displayed as yield :image with
<% content_for :image do %>
<%# Everything here will be displayed outside of the wraper %>
<% end %>
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