简单的正则表达式来替换 URL 的第一部分 [英] Simple regex to replace first part of URL

问题描述

给定

• http://localhost:3000/something
• http://www.domainname.com/something
• https://domainname.com/something

如何选择 /something 之前的任何内容并将其替换为 staticpages?

How do I select whatever is before the /something and replace it with staticpages?

输入 URL 是 request.referer 的结果，但由于你不能 render request.referer(而且我不想要 redirect_to)，我正在尝试使用 controller/action 手动构建适当的模板，其中 action 始终是路由，我只需要替换域使用控制器 staticpages.

The input URL is the result of a request.referer, but since you can't render request.referer (and I don't want a redirect_to), I'm trying to manually construct the appropriate template using controller/action where action is always the route, and I just need to replace the domain with the controller staticpages.

推荐答案

你可以使用这样的正则表达式:

You could use a regex like this:

(https?://)(.*?)(/.*)

工作演示

正如您在替换部分中看到的，您可以使用捕获组并连接您想要生成所需网址的字符串.

As you can see in the Substitution section, you can use capturing group and concatenates the strings you want to generate the needed urls.

正则表达式的思路是捕获域前后的字符串，使用\1 + staticpages + \3.

The idea of the regex is to capture the string before and after the domain and use \1 + staticpages + \3.

如果您想将协议更改为 ftp，您可以使用捕获组索引并使用此替换字符串:

If you want to change the protocol to ftp, you could play with capturing group index and use this replacement string:

ftp://\2\3

所以，你会:

ftp://localhost:3000/something
ftp://www.domainname.com/something
ftp://domainname.com/something

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