如何使用 Cargo 构建多个二进制文件? [英] How can I build multiple binaries with Cargo?

问题描述

我想制作一个带有 daemon 和 client 的项目，通过 unix 套接字连接.

client 和 daemon 需要两个二进制文件，那么我如何告诉 Cargo 从两个不同的来源构建两个目标?

为了增加一点幻想，我想有一个 library 作为 daemon 的主要部分，并且只有一个二进制文件来包裹它，通过套接字进行通信.

所以，我们有这种树结构:

├── Cargo.toml├──目标|└── 调试|├── 守护进程│ └── 客户└── src├── 守护进程│ ├── bin│ │ └── main.rs│ └── lib│ └── lib.rs└── 客户└── 斌└── main.rs

我可以制作一个同时管理这两个问题的可执行文件，但这不是我想要做的，除非这是非常好的做法.

解决方案

你可以使用 [[bin]] 指定多个二进制文件，正如前面提到的 此处:

[[bin]]名称 = "守护进程"path = "src/daemon/bin/main.rs"[[斌]]名称 = "客户"path = "src/client/bin/main.rs"

提示:如果你把这些文件放在 src/bin/daemon.rs 和 src/bin/client.rs 中，你会得到两个名为 daemon 和 client as Cargo 将 src/bin 中的所有文件自动编译为同名的可执行文件.仅当您不遵循此约定时，才需要像上面的代码片段一样指定名称和路径.

I'd like to make a project with a daemon and a client, connecting through a unix socket.

A client and a daemon requires two binaries, so how do I tell Cargo to build two targets from two different sources?

To add a bit of fantasy, I'd like to have a library for the main part of the daemon, and just have a binary to wrap around it and communicate through sockets.

So, we have this kind of tree architecture:

├── Cargo.toml
├── target
|   └── debug
|       ├── daemon
│       └── client
└── src
    ├── daemon
    │   ├── bin
    │   │   └── main.rs
    │   └── lib
    │       └── lib.rs
    └── client
        └── bin
            └── main.rs

I could make one executable which manages both concerns, but that's not what I want to do, unless it's very good practice.

解决方案

You can specify multiple binaries using [[bin]], as mentioned here:

[[bin]]
name = "daemon"
path = "src/daemon/bin/main.rs"

[[bin]]
name = "client"
path = "src/client/bin/main.rs"

Tip: If you instead put these files in src/bin/daemon.rs and src/bin/client.rs, you'll get two executables named daemon and client as Cargo compiles all files in src/bin into executables with the same name automatically. You need to specify names and paths like in the snippet above only if you don't follow this convention.

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