如何编写一个返回 Vec<Path> 的函数? [英] How to write a function that returns Vec&lt;Path&gt;?

问题描述

我正在阅读文档并尝试编写一些基本的文件 I/O 代码作为帮助我学习 Rust 的工具.

I'm reading the documentation and trying to write some basic file I/O code as a vehicle to help me learn Rust.

以下内容无法编译:

use std::fs;
use std::io;
use std::path::Path;

pub fn read_filenames_from_dir<P>(path: P) -> Result<Vec<Path>, io::Error>
where
    P: AsRef<Path>,
{
    let paths = try!(fs::read_dir(path));
    Ok(paths.unwrap())
}

出现编译错误:

error[E0277]: the trait bound `[u8]: std::marker::Sized` is not satisfied in `std::path::Path`
  --> src/main.rs:5:1
   |
5  | / pub fn read_filenames_from_dir<P>(path: P) -> Result<Vec<Path>, io::Error>
6  | | where
7  | |     P: AsRef<Path>,
8  | | {
9  | |     let paths = try!(fs::read_dir(path));
10 | |     Ok(paths.unwrap())
11 | | }
   | |_^ `[u8]` does not have a constant size known at compile-time
   |
   = help: within `std::path::Path`, the trait `std::marker::Sized` is not implemented for `[u8]`
   = note: required because it appears within the type `std::path::Path`
   = note: required by `std::vec::Vec`

我应该如何编写这个函数来返回传入的Path中的Path的集合?

How should I write this function to return the collection of Paths inside the Path that's passed in?

推荐答案

你没有.Path 是一种没有大小的类型，只能通过间接方式使用(例如 &Path 或 Box).从这个意义上说，它就像 str 或 [u8] 类型——两者都不能直接使用，只能间接使用.

You don't. Path is a type that has no size, and is only usable through indirection (such as &Path or Box<Path>). In this sense, it is like the type str or [u8] — neither can be directly used, only indirectly.

您可能想要的是 PathBuf，表示拥有的路径.它相当于 &str 的 String 和 &[u8] 的 Vec.

What you probably want is a PathBuf, which represents an owned path. It is the equivalent of String for &str and Vec<u8> for &[u8].

更改返回类型后，您必须正确映射迭代器的结果以创建您想要的类型:

After changing the return type, you have to properly map the results of the iterator to create your desired type:

use std::{
    fs, io,
    path::{Path, PathBuf},
};

pub fn read_filenames_from_dir<P>(path: P) -> Result<Vec<PathBuf>, io::Error>
where
    P: AsRef<Path>,
{
    fs::read_dir(path)?
        .into_iter()
        .map(|x| x.map(|entry| entry.path()))
        .collect()
}

fn main() {
    println!("{:?}", read_filenames_from_dir("/etc"));
}

另见:

• `str` 在编译时没有已知的恒定大小"是什么意思，最简单的修复方法是什么

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