错误的数组？坏的foreach？ [英] Bad array? Bad foreach?

问题描述

对不起，关于这个专题的巨大的无知，但我真的不知道去哪里找比其他这个网站的时候我接触到我的PHP的麻烦。

Sorry for the huge ignorance on the topic, but I really have no idea where to look other than this website when I come into trouble with my PHP.

我想在这里做的是使用pre指定的ID从数据库中调用特定的电影。但我得到的是一个'（）提供的foreach无效参数在第二和第三的foreach的下方。

What I'm trying to do here is use pre-designated IDs to call particular movies from a database. But all I get is an 'Invalid argument supplied for foreach()' message on the second and third foreach's below.

下面是在我的头上code：

Here's my code in the head:

//Custom lists of movies to bring in
//New Releases list
 $films_new_releases = array(40805, 46705, 41630, 44564, 39451, 20352, 43933, 49009, 49797, 42194);
 //Most Popular list
 $films_most_popular = array(27205, 16290, 10138, 41733, 37799, 18785, 19995, 17654, 10140, 12162);

//Get information from address bar
$list = $_GET['l'];
if ($list == 'new releases') {
    $list_chosen = $films_new_releases;
}
elseif ($list == 'most popular') {
    $list_chosen = $films_most_popular;
}
else {
    $list_chosen = $films_new_releases;
}

和中跻身正文：

  // Loop through each film returned
  foreach ($list_chosen as $list_chosen_film) {

    $films_result = $tmdb->getMovie($list_chosen_film);
    $film = json_decode($films_result);

    // Set default poster image to use if film doesn't have one
    $backdrop_url = 'images/placeholder-film.gif';

    // Loop through each poster for current film
    foreach($film->backdrops as $backdrop) {
      if ($backdrop->image->size == 'poster') {
        $backdrop_url = $backdrop->image->url;
      }
    }

    echo '<div class="view-films-film">
        <a href="film.php?id=' . $film->id . '"><img src="' . $backdrop_url . '" alt="' . $film->name . '" /></a>
            <div class="view-films-film-snippet">
                <h2><a href="film.php?id=' . $film->id . '">' . $film->name . '</a></h2>';
    if ($film->certification != null) {
           echo '<img src="images/bbfc-' . strtolower($film->certification) . '.png" alt="" />';
    }
    echo '      <h3>Starring</h3>
                <p>';
    $num_actors = 0;
    foreach ($film->cast as $cast) {
    if ($cast->job == 'Actor') {
      echo '<a href="person.php?id=' . $cast->id . '">' . $cast->name . '</a> ';
      $num_actors++;
      if ($num_actors == 5)
        break;
    }
    echo '      </p>
                <h3>Director</h3>
                <p>';
    foreach ($film->cast as $cast) {
        if ($cast->job == 'Director') {
            echo '<a href="person.php?id=' . $cast->id . '">' . $cast->name . '</a> ';
        }
    }
    echo '      </p>
            </div>
        </div>';
  }
  // End films
  }

小测试中，我所做的就是检查什么 $ list_chosen ， $ list_chosen_film ， $ films_result 和 $电影实际上通过在页面的底部打印它们包含的内容。

The little testing I've done is checking what $list_chosen, $list_chosen_film, $films_result and $film actually contain by printing them at the bottom of the page.

$ list_chosen 显示 - 阵列， $ list_chosen_film 节目 - 42194 ， $ films_result 显示整个JSON字符串， $电影显示 - 阵列

$list_chosen shows - Array, $list_chosen_film shows - 42194, $films_result shows the entire JSON string, $film shows - Array.

推荐答案

尝试添加：

print_r($film->backdrop);

第二前的foreach（）循环。该错误消息之前它不会是一个数组或它将包含零个元素（不允许）。如果您还补充：

before the second foreach() loop. Before the error message it won't be an array or it will contain zero elements (not allowed). If you also add:

echo $films_result;

您将能够调试并完全理解什么是错的。如果没有，张贴在你的问题，整个输出。

you will be able to debug it and fully understand what is wrong. If not, post the whole output in your question.

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