如何组阵列和尽数 [英] how to group array and count them

问题描述

我有数组这样

  $ ARR =阵列（1,1,1,2,2,3,3,1,1,2,2,3）;
 

我发现一个函数 array_count_values​​ 。但它会组中的所有相同的值并计算所有这些，打破序列。

  $结果[1] = 5
$结果[2] = 4
$结果[3] = 3
 

如何创建计数阵列组将按照顺序。结果我真正想要的是：

  [1] = 3;
[2] = 2;
[3] = 2;
[2] = 2;
[3] = 1;
 

解决方案

它可以简单地手工完成：

  $ ARR =阵列（1,1,1,2,2,3,3,1,1,2,2,3）;$结果=阵列（）;
$prev_value =阵列（'值'=＆GT;空，'量'=＆GT; NULL）;的foreach（$改编为$ VAL）{
    如果（$prev_value ['值']！= $ VAL）{
        未设置（$prev_value）;
        $prev_value =阵列（'值'= GT; $ VAL，'量'= 0）;
        $结果[] =＆放大器; $prev_value;
    }    $prev_value ['量'] ++;
}后续代码var_dump（$结果）;
 

i have array like this

$arr = array(1,1,1,2,2,3,3,1,1,2,2,3);

i found one function array_count_values. but it will group all same value and count them all and break the sequence.

$result[1] = 5
$result[2] = 4
$result[3] = 3

how to create group of count array that will follow the sequence. the result i really want is :

[1] = 3;
[2] = 2;
[3] = 2;
[2] = 2;
[3] = 1;

解决方案

It can be done simply manually:

$arr = array(1,1,1,2,2,3,3,1,1,2,2,3);

$result = array();
$prev_value = array('value' => null, 'amount' => null);

foreach ($arr as $val) {
    if ($prev_value['value'] != $val) {
        unset($prev_value);
        $prev_value = array('value' => $val, 'amount' => 0);
        $result[] =& $prev_value;
    }

    $prev_value['amount']++;
}

var_dump($result);

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