Rust 中的逻辑运算符会短路吗? [英] Do logical operators short-circuit in Rust?

问题描述

&& 和 || 是否会在知道结果后立即停止计算?换句话说将 (true == true) ||(true == false) 不对右侧求值，因为在仅对左侧求值后，整个表达式已知为 true.

Do && and || stop evaluating as soon as a result is known? In other words will (true == true) || (true == false) not evaluate the right side because the whole expression is known to be true after only evaluating the left side.

推荐答案

是.

来自 Rust 参考:

fn main() {
    let x = false || true; // true
    let y = false && panic!(); // false, doesn't evaluate `panic!()`
}

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