Rust 从 fn 返回结果错误:类型不匹配 [英] Rust returns a result error from fn: mismatched types
问题描述
我希望这个函数返回一个错误结果:
I want this function to return an error result:
fn get_result() -> Result<String, std::io::Error> {
// Ok(String::from("foo")) <- works fine
Result::Err(String::from("foo"))
}
错误信息
error[E0308]: mismatched types
--> src/main.rs:3:17
|
3 | Result::Err(String::from("foo"))
| ^^^^^^^^^^^^^^^^^^^ expected struct `std::io::Error`, found struct `std::string::String`
|
= note: expected type `std::io::Error`
found type `std::string::String`
我很困惑如何在使用预期结构时打印出错误消息.
I'm confused how I can print out an error message when using the expected struct.
推荐答案
错误信息很清楚.get_result
的返回类型是 Result
,这意味着在 Result::Ok
的情况下,Ok
变体的内部值是 String
类型,而在 Result::Err
情况下, 的内部值Err
变体属于 std::io::Error
类型.
The error message is quite clear. Your return type for get_result
is Result<String, std::io::Error>
, meaning that in the Result::Ok
case, the inner value of the Ok
variant is of type String
, whereas in the Result::Err
case, the inner value of the Err
variant is of type std::io::Error
.
您的代码试图创建一个具有 String
类型内部值的 Err
变体,并且编译器正确地抱怨类型不匹配.要创建新的 std::io::Error
,您可以使用 new
在 std::io::Error
上的方法.以下是使用正确类型的代码示例:
Your code attempted to create an Err
variant with an inner value of type String
, and the compiler rightfully complains about a type mismatch. To create a new std::io::Error
, you can use the new
method on std::io::Error
. Here's an example of your code using the correct types:
fn get_result() -> Result<String, std::io::Error> {
Err(std::io::Error::new(std::io::ErrorKind::Other, "foo"))
}
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