如何使用生成器函数初始化 Rust 向量? [英] How to init a Rust vector with a generator function?

问题描述

在语言之间切换可能会很痛苦.一种语言的习语感觉很好"，人们开始在其他语言中寻找相同的习语.

Hopping between languages can be painful. Idioms of one language "feel good" and one starts to look for the same idioms in other languages.

在 F# 中，有一种方法可以借助生成器函数来初始化数组.Array.init n 生成器.现在，我跳到 Rust 了一段时间，我想知道是否有类似的设施，或者我是否必须为自己创建这样的设施.

In F#, there is a way to init an array with the help of a generator function. Array.init n generator. Now, that I hopped to Rust for a little while, I wonder if there is a similar facility in place or if I have to create myself such a facility.

学习 关于向量的 Rust 标准库文档，我可以找不到与我要查找的内容类似的内容.

Studying Rust standard library documentation about vectors, I could not find anything similar to what I am looking for.

// Looking for something similar to:
Vec<T>::init(n : usize, generator : F) -> Vec<T> 
    where F: Fn(usize) -> T {
    // ...
}

也许它在 Rust 中的工作方式不同，通过迭代器.但我必须承认，Rust 迭代器(以及它们的无数种风格)在我的头脑中仍然有点模糊.

Maybe it works differently in Rust, by means of iterators. But I must admit, that Rust iterators (and their myriads of flavors) are still a tad foggy to my simple mind.

推荐答案

您可以将 range 与 map 一起使用，然后收集结果.

You can use a range withing a map and then collect the results.

就像在 F# 文档的示例中一样:

Like in the example for F# docs:

let my_vector : Vec<i32> = (1..11).map(|x| x*x).collect();

检查这个游乐场

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