使用 Java 中的 Reactive Extensions 对对象集合进行排序? [英] Sort collection of objects with Reactive Extensions in Java?
本文介绍了使用 Java 中的 Reactive Extensions 对对象集合进行排序?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
如何使用 rxjava 根据对象的一个或多个字段对对象集合进行排序?
How can I can sort a collection of objects using rxjava based on one or more fields of the objects?
public class Car {
public String model;
public int numberOfWheels;
public String color;
public int yearOfProduction;
}
List<Car> cars = new ArrayList<>();
cars.add(...);
cars.add(...);
Observable<List<Car>> getCars() { Observable.just(cars) };
Observable<List<Car>> getCarsSortedByModel() { ??? };
Observable<List<Car>> getCarsSortedByColor() { ??? };
Observable<List<Car>> getCarsSortedByModelAndColor() { ??? };
推荐答案
Observable.toSortedList
将返回 Observable
:>
public class Car {
public String model;
public int numberOfWheels;
public String color;
public int yearOfProduction;
public static void main(String[] args) {
cars()
.toSortedList(Car::compareModel)
.subscribe(System.out::println) ;
cars()
.toSortedList(Car::compareYear)
.subscribe(System.out::println) ;
}
private static Integer compareModel(Car car1, Car car2) {
return car1.model.compareTo(car2.model);
}
private static Integer compareYear(Car car1, Car car2) {
return Integer.valueOf(car1.yearOfProduction)
.compareTo(car2.yearOfProduction);
}
private static Observable<Car> cars(){
Car car1 = new Car();
car1.model = "robin";
car1.color = "red";
car1.numberOfWheels = 3;
car1.yearOfProduction = 1972;
Car car2 = new Car();
car2.model = "corolla";
car2.color = "white";
car2.numberOfWheels = 4;
car2.yearOfProduction = 1992;
return Observable.just(car1, car2);
}
public String toString(){
return model;
}
}
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