这里发生在for循环 [英] What's happening here in this for loop

问题描述

我是想别的东西却突然卡住这个无限循环。
请建议与解释的答案怎么在这里就在下面的for循环

I was trying something else but suddenly stuck with this infinite loop . Please suggest an answer with explanation that what's going on here in the below for loop

#include<stdio.h>

int main()
{
 int x=0;
 int i;
 int array[5];
 for(i=0;i<=5;i++)
 {
  array[i]=x;
  printf("#%d value set in index %d\n",x,i);
 }

 return 0;
}

当我删除 = 登录的条件循环正常工作。

When I remove = sign in the condition of for loop It works fine.

但是，当我把这个它进入无限循环，为什么呢？
数组访问额外的元素（比限值）是未定义的行为还是什么？
任何帮助将AP preciated。
先谢谢了。

But when I put this it goes to infinite loop , Why? Accessing extra element (more than its limit) in array is undefined behaviour or what ? Any help will appreciated. Thanks in advance.

〜

推荐答案

要避免造成这样的错误，因为很容易，这里有两个很好的规则编写为遍历实际（本地）数组：

To avoid causing errors like this as easily, here's two good rules for writing for loops over actual (local) arrays:

1. 迭代开始于指数为0，由于C的数组是从0开始。


2. 使用＆LT; ，始终。决不＆LT; =


3. 请不要重复大小，让编译器使用的sizeof数组/ * sizeof的阵列计算它。请注意，在第二个任期内的星号。

1. Iteration starts at index 0, since C's arrays are 0-based.
2. Use <, always. Never <=.
3. Don't repeat the size, let the compiler compute it using sizeof array / sizeof *array. Note the asterisk in the second term.

所以，这个循环应该已被写入：

So, this loop should have been written:

for(i = 0; i < sizeof array / sizeof *array; i++)

，然后你会一直是安全的。

and then you would have been safe.

请注意，这仅适用于真正的阵列具有规模可见的sizeof ，如果你让阵列崩溃为指针它赢得将不起作用。

Note that this only works for "real" arrays that have a size visible to sizeof, if you've let the array "collapse" into a pointer it won't work.

另外请注意，的sizeof 不是一个功能，因此无需（）是围绕其在案件的说法必要像这样的。

Also note that sizeof is not a function, so no ()s are necessary around its argument in cases like these.

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