从数组壳中取出元素 [英] Remove element from array shell

问题描述

我需要在bash shell中的数组中删除元素。
一般来说，我会简单地做：

I need to remove an element from an array in bash shell. Generally I'd simply do:

array=("${(@)array:#<element to remove>}")

不幸的是我要删除的元素是一个变量，所以我不能用previous命令。
到这里一个例子：

Unfortunately the element I want to remove is a variable so I can't use the previous command. Down here an example:

array+=(pluto)
array+=(pippo)
delete=(pluto)
array( ${array[@]/$delete} ) -> but clearly doesn't work because of {}

任何想法？

推荐答案

，你想在下面的作品庆典和的zsh ：

The following works as you would like in bash and zsh:

$ array=(pluto pippo)
$ delete=(pluto)
$ echo ${array[@]/$delete}
pippo
$ array=( "${array[@]/$delete}" )

如果需要删除多个元素：

If need to delete more than one element:

...
$ delete=(pluto pippo)
for del in ${delete[@]}
do
   array=(${array[@]/$del})
done

买者

该技术也会删除prefixes匹配 $删除从元素，不一定所有元素。

This technique actually removes prefixes matching $delete from the elements, not necessarily whole elements.

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