硬code字节数组用C [英] hardcode byte array in C

问题描述

我调试网络应用程序。

我必须模拟一些，以使应用程序工作交换的数据。在C ++中，你可以这样做

I have to simulate some of the data exchanged in order for the application to work. In C++ you can do something like

char* myArray = { 0x00, 0x11, 0x22 };

不过，我似乎无法找到一个C相当于此语法。

However, I can't seem to find a C equivalent for this syntax.

基本上，我只是想填补硬codeD值的数组。

Basically I just want to fill an array with hard coded values.

推荐答案

您可以做同样的事情在C，但你应该申报类型的char [] 吧，没有的char * ，这样就可以得到它与的sizeof 运营商尺寸：

You can do the same thing in C, but you should declare it of type char[], not char*, so that you can get its size with the sizeof operator:

char myArray[] = { 0x00, 0x11, 0x22 };
size_t myArraySize = sizeof(myArray);  // myArraySize = 3

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