转义字符在 SAS 中解释为数组 [英] Escape characters interpreted as array in SAS

问题描述

我使用的是 SAS 大学版.

I am using SAS university edition.

我想为以下数据集使用一个名为Age(years)"而不是Age_years"的变量.我知道()"将被解释为数组，而我需要它成为变量的一部分.

I want to have a variable named "Age(years)" instead of "Age_years" for the following data set. I understand that "()" will be interpreted as array, while I need this to be a part of the variable.

data data;
  input Name $ Age_years Gender $;
  datalines;
    Dino 6 male
    Rita 5 female
    Aurora 6 female
    Joko 7 male
  ;
run;

我访问以下行时的确切错误是错误:引用了未声明的数组:年龄.错误:变量年龄尚未声明为数组."

The exact error when I am accessing the following line is " ERROR: Undeclared array referenced: Age. ERROR: Variable Age has not been declared as an array."

 data data;
  set data;
  Age(years)=Age_years;
 run;

我已经检查了转义这个括号字符的可能性，这样它就不会被解释为数组，如下所示:SAS 中的特殊字符 但是 % 符号无助于转义 () 字符.如何在 SAS 中执行此操作?

I have checked for possibility of escaping this bracket characters so that it won't be interpreted as array as in here : Special Characters in SAS however the % symbol does not help to escape the () characters. How can I do this in SAS?

推荐答案

您可以将n"称为修饰符.您可以将一些附加到引用文字的末尾以指定 SAS 应如何处理它:

You could call that 'n' a modifier. There are a few you can append to the end of a quoted literal to specify how SAS should treat it:

'my variable'n 将被视为名为 'my variable' 的变量

'my variable'n will be treated as a variable called 'my variable'

'14AUG2017'd 将被视为代表今天日期的数字

'14AUG2017'd will be treated as a number representing today's date

'14AUG2017:09:53:00'dt 将被视为代表今天日期和时间的数字

'14AUG2017:09:53:00'dt will be treated as a number representing today's date and time

'49'x 将被视为字母 A，此处由其十六进制值指定.

'49'x will be treated as the letter A, here specified by its hexadecimal value.

...以及我可能忘记的其他人.

...and others I may have forgotten.

请注意，使用非 SAS 有效名称不被认为是好的做法.

Note that it is not considered good practice to use non SAS-valid names.

指向 SAS 支持的链接

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