从列表动态创建类的函数 [英] Function to dynamically create classes from lists

问题描述

我对 SASS 还很陌生，我对列表的工作方式感到困惑.我有一个这样的多维列表:

Im fairly new to SASS and I'm confused by the way lists work. I have a multidimensional list like this:

$stylethemes: {
  (15, bold, red),
  (12, normal, blue)
}

我现在想要一个函数，它为 $stylethemes 中的每个列表创建一个类，然后将该列表的值放入该类中.我想从上面的列表中得到的输出是这样的:

I now want a function that makes a class for each list in $stylethemes and then puts the values of that list into that class. The output I want from the above list is this:

.theme1{
   font-size: 15;
   font-weight: bold;
   color: red;
}

.theme2{
   font-size: 12;
   font-weight: normal;
   color: blue;
}

谁能告诉我如何做到这一点?提前致谢.

Can anyone show me how I can do this? Thanks in advance.

推荐答案

产生预期结果的代码如下所示:

The code to produce the desired results would look like this:

$stylethemes: (
  (15, bold, red),
  (12, normal, blue)
);

@for $i from 1 through length($stylethemes) {
  .theme#{$i} {
    font-size: nth(nth($stylethemes, $i), 1);
    font-weight: nth(nth($stylethemes, $i), 2);
    color: nth(nth($stylethemes, $i), 3);
  }
}

但是，您会发现这不是特别灵活.您最好使用属性/值的映射，这样您就不必保证特定的顺序:

However, you'll find this isn't particularly flexible. You're better off using mappings for the property/values so that you don't have to guarantee a specific order:

$stylethemes: (
  (font-size: 15, font-weight: bold, color: red),
  (font-size: 12, font-weight: normal, color: blue)
);

@for $i from 1 through length($stylethemes) {
  .theme#{$i} {
    @each $prop, $val in nth($stylethemes, $i) {
      #{$prop}: $val;
    }
  }
}

或

$stylethemes: (
  theme1: (font-size: 15, font-weight: bold, color: red),
  theme2: (font-size: 12, font-weight: normal, color: blue)
);

@each $theme, $properties in $stylethemes {
  .#{$theme} {
    @each $prop, $val in $properties {
      #{$prop}: $val;
    }
  }
}

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