将列表元素作为参数传递给 mixin [英] Passing list elements as arguments to a mixin

问题描述

除了当我尝试将 $gradient 传递给 @include background-image 时，以下代码都有效.

The following code works except for when I try to pass the $gradient to @include background-image.

@mixin compositeFill($size: 100px, $gradient:(top, #000000 0%, #FFFFFF 100%)) {

    $isTop: nth($gradient, 1) == "top";
    $direction: if($isTop, vertical, horizontal);
    $widthHeight: if($isTop, height, width);
    $heightWidth: if($isTop, width, height);

    // snipped a whole bunch of irrelevant stuff
    // this is what fails:
    @include background-image(linear-gradient($gradient));
}

如何将列表(例如 $gradient)传递给需要多个参数的 mixin?

How to pass a list (e.g. $gradient) to a mixin that expects multiple arguments?

推荐答案

要将参数列表传递给接受多个参数的 mixin，您可能希望像这样使用它:

To pass a list of parameters to a mixin that accepts multiple parameters you would want to use it like this:

@include background-image(linear-gradient($gradient...));

三个点 表示您要填充列表元素中的参数……否则整个列表将作为单个参数传递……而 linear-gradient() mixin 失败(因为它需要至少两个颜色停止参数).

the three dots indicate that you want to fill in the arguments from the list elements ... otherwise the whole list is passed as a single argument ... and the linear-gradient() mixin fails (as it expects at least two color stop arguments).

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