phpsass 返回一个致命错误 [英] phpsass returns a fatal error

问题描述

我正在使用一个非常简单的代码来测试 phpsass

I am using a very simple code to test phpsass

$sass = new SassParser();
$c = file_get_contents('/_www/_projects/cdn/public_html/test/test.sass');
$css = $sass->toCss($c);

sass 文件非常基础:

The sass file is very basic:

$blue: #3bbfce;
$margin: 16px;

table.hl {
  margin: 2em 0;
  td.ln {
    text-align: right;
  }
}

li {
  font: {
    family: serif;
    weight: bold;
    size: 1.2em;
  }
}

.content-navigation {
  border-color: $blue;
  color:
    darken($blue, 9%);
}

.border {
  padding: $margin / 2;
  margin: $margin / 2;
  border-color: $blue;
}

我收到以下错误:

致命错误:在 D:\_www\_git\phpsass\script\literals\SassNumber.php 中第 201 行出现未捕获的异常 'SassNumberException' 和消息 '

Fatal error: Uncaught exception 'SassNumberException' with message ' in D:\_www\_git\phpsass\script\literals\SassNumber.php on line 201

SassNumberException: Number must be a number: Array::26 Source: padding: $margin/2;在 D:\_www\_git\phpsass\script\literals\SassNumber.php 第 201 行

SassNumberException: Number must be a number: Array::26 Source: padding: $margin / 2; in D:\_www\_git\phpsass\script\literals\SassNumber.php on line 201

如果有帮助的话，之前还抛出了以下提示(我尝试更改error_reporting级别，但是提示消失当然没有解决问题):

If it can help, there's also the following notice thrown before (I tried to change the error_reporting level but having the notice disappear of course didn't solve the problem):

注意:第 25 行 D:\_www\_git\phpsass\SassException.php 中的数组到字符串的转换

Notice: Array to string conversion in D:\_www\_git\phpsass\SassException.php on line 25

如果我在 http://www.phpsass.com 上对他们的在线 PHP 编译器使用相同的 sass 代码/try/ 它编译正确...我不明白

If I use the same sass code against their online PHP compiler at http://www.phpsass.com/try/ it compiles correctly... I don't get it

推荐答案

事实上，这是一个纯粹的语法问题.我试图从 sass 代码中删除变量，并意识到它有效 - 效果不佳(margin: 2em 0 变成了 margin: 20)，但不再有错误.

In fact that was a pure syntaxic problem. I tried to remove the variables from the sass code, and realized it worked - not well (margin: 2em 0 became margin: 20) but there was no error anymore.

我从 http://sass-lang.com/ 获取的 sass 片段不是 sass 而是.scss 格式.SassParser 类有一个参数叫syntax，默认设置为'sass'，调用$scss = new SassParser(['syntax' => 'scss']).

The sass snippets that I took from http://sass-lang.com/ were not sass but scss format. The SassParser class has a parameter called syntax, which is set to 'sass' by default and needs to be set to scss when calling $scss = new SassParser(['syntax' => 'scss']).

但是我需要解析一个字符串，而不是一个文件，但是如果你传递一个带有 scss 扩展名的文件，你就不需要这个额外的参数.

However I needed to parse a string, not a file, but if you pass a file with a scss extension you don't need this extra parameter.

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