在 Scala 中，是否可以压缩两个不同大小的列表? [英] In Scala, is it possible to zip two lists of differing sizes?

问题描述

例如假设我有

val letters = ('a', 'b', 'c', 'd', 'e')
val numbers = (1, 2)

是否可以生成一个列表

(('a',1), ('b',2), ('c',1),('d',2),('e',1))

推荐答案

您的字母和数字是元组，而不是列表.所以让我们解决这个问题

Your letters and numbers are tuples, not lists. So let's fix that

scala> val letters = List('a', 'b', 'c', 'd', 'e')
letters: List[Char] = List(a, b, c, d, e)

scala> val numbers = List(1,2)                    
numbers: List[Int] = List(1, 2)

现在，如果我们压缩它们，我们不会得到想要的结果

Now, if we zip them we don't get the desired result

scala> letters zip numbers
res11: List[(Char, Int)] = List((a,1), (b,2))

但这表明如果数字无限重复，那么问题就会解决

But that suggests that if numbers were repeated infinitely then the problem would be solved

scala> letters zip (Stream continually numbers).flatten
res12: List[(Char, Int)] = List((a,1), (b,2), (c,1), (d,2), (e,1))

不幸的是，这是基于数字比字母短的知识.所以把它全部解决

Unfortunately, that's based on knowledge that numbers is shorter than letters. So to fix it all up

scala> ((Stream continually letters).flatten zip (Stream continually numbers).flatten take (letters.size max numbers.size)).toList
res13: List[(Char, Int)] = List((a,1), (b,2), (c,1), (d,2), (e,1))

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