获取类名和属性名来自EX pression（）=＆GT; MyClass.Name [英] Get class name and property name from an expression () => MyClass.Name

问题描述

这是MOT可能是重复的，但我无法找到一个合适的问题。

This is mot likely a duplicate, but I couldn't find a proper question.

我想获得MyClass.Name从（）=＆GT; MyClass.Name 。如何定义方法的参数以及如何转换前pression为一个字符串？

I want to get "MyClass.Name" from () => MyClass.Name. How do I define the method parameter and how do I convert the expression to a string?

推荐答案

这是一个防爆pression＆LT; Func键＆LT;字符串＆GT;＆GT; ，所以你可以有

That is an Expression<Func<string>>, so you could have:

void Foo(Expression<Func<string>> selector) {...}

或

void Foo<T>(Expression<Func<T>> selector) {...}

不过，请注意语法 MyClass.Name 指的静态的财产;如果你想要一个的实例的属性，你可能需要的东西更像是一个防爆pression＆LT; Func键＆LT; MyClass的，串＆GT;＆GT; - 例如

however, note that the syntax MyClass.Name refers to a static property; if you want an instance property you might need something more like an Expression<Func<MyClass,string>> - for example:

static void Foo<TSource, TValue>(
    Expression<Func<TSource, TValue>> selector)
{

}
static void Main() {
     Foo((MyClass obj) => obj.Name);        
}

至于执行; 在这个简单的情况下，，我们可以预期车身是一个 MemberEx pression ，这样：

As for implementation; in this simple case, we can expect the Body to be a MemberExpression, so:

static void Foo<TSource, TValue>(
    Expression<Func<TSource, TValue>> selector)
{
    var member = ((MemberExpression)selector.Body).Member;
    Console.WriteLine(member.ReflectedType.Name + "." + member.Name);
}

然而，在一般情况下更加复杂。这也将工作，如果我们使用静态成员：

However, it is more complex in the general case. This will also work if we use the static member:

static void Foo<TValue>(
    Expression<Func<TValue>> selector)
{
    var member = ((MemberExpression)selector.Body).Member;
    Console.WriteLine(member.ReflectedType.Name + "." + member.Name);
}

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