Scala Tour 隐式转换示例 [英] Scala Tour Implicit Conversion Example

问题描述

我很难理解这段代码到底做了什么:

I am having a hard time understanding what this piece of code does exactly:

import scala.language.implicitConversions

implicit def list2ordered[A](x: List[A])
    (implicit elem2ordered: A => Ordered[A]): Ordered[List[A]] =
  new Ordered[List[A]] { 
    //replace with a more useful implementation
    def compare(that: List[A]): Int = 1
  }

它来自 Scala Tour，位于隐式转换"部分.我知道 list2ordered 需要一个 List[A] 来自 List(1, 2, 3) <= List(4,5) compare 函数中的 和 that 是右侧.

It comes from the Scala Tour and it is in the section "Implicit Conversions". I understand that list2ordered takes a List[A] that comes from the left hand side of List(1, 2, 3) <= List(4, 5) and that in compare function is the right hand side.

然而，为什么 A =>Ordered[A] 而不是 List[A] =>有序[列表[A]] ?我对这段代码的实际作用有点困惑.

However, why is A => Ordered[A] that and not List[A] => Ordered[List[A]] ? I am a bit confused as to what this piece of code actually does.

推荐答案

你的困惑是可以理解的.示例代码并不是非常有启发性，主要是因为代码，如所呈现的，不需要 A-to-Ordered[A] 转换.我们可以将其注释掉，一切仍然有效"(如其所是).

Your confusion is understandable. The example code isn't terribly illuminating largely because the code, as presented, doesn't need the A-to-Ordered[A] conversion. We can comment it out and everything still "works" (such as it is).

import scala.language.implicitConversions

implicit def list2ordered[A](xs: List[A]
                          //)(implicit elem2ordered: A => Ordered[A]
                             ): Ordered[List[A]] =
  new Ordered[List[A]] {
    def compare(ys: List[A]): Int = 
      1 //this is always greater than that
  }

我们甚至可以实现一个有意义的(如果头脑比较简单的话)List 排序，并且仍然不需要 A-to-Ordered[A] 转化.

We can even implement a meaningful (if rather simple minded) List ordering and still not need the A-to-Ordered[A] conversion.

import scala.language.implicitConversions

implicit def list2ordered[A](xs: List[A]
                          //)(implicit elem2ordered: A => Ordered[A]
                             ): Ordered[List[A]] =
  new Ordered[List[A]] {
    def compare(ys: List[A]): Int =
      xs.length - ys.length //shorter List before longer List
  }

但是如果 List 顺序取决于元素顺序，那么我们需要这种转换.

But if List order depends on element order, then we need that conversion.

import scala.language.implicitConversions

implicit def list2ordered[A](xs: List[A]
                            )(implicit elem2ordered: A => Ordered[A]
                             ): Ordered[List[A]] =
  new Ordered[List[A]] {
    //3rd element determines order
    def compare(ys: List[A]): Int = (xs.lift(2),ys.lift(2)) match {
      case (None,None) => 0
      case (None, _)   => -1
      case (_, None)   => 1
      case (Some(x), Some(y)) => 
        x compare y //implicit conversion needed
    }
  }

为了说明重点，让我们通过修改所需的转换来简化这种按 3rd-element 排序的排列.

Just to drive home the point, let's simplify this order-by-3rd-element arrangement by modifying the required conversion.

import scala.language.implicitConversions

implicit def list2ordered[A](xs: List[A]
                            )(implicit elem2ordered: Option[A] => Ordered[Option[A]]
                             ): Ordered[List[A]] =
  new Ordered[List[A]] {
    def compare(ys: List[A]): Int =
      xs.lift(2) compare ys.lift(2)  //3rd element determines order
  }

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