删除火花字符串列的第一个字符 [英] remove first character of a spark string column
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问题描述
正如我在标题中所说,我想知道如何删除火花字符串列的第一个字符,对于以下两种情况:
I wonder as I said in title how to remove first character of a spark string column, for the two following cases:
val myDF1 = Seq(("£14326"),("£1258634"),("£15626"),("£163262")).toDF("A")
val myDF2 = Seq(("a14326"),("c1258634"),("t15626"),("f163262")).toDF("A")
myDF1.show
myDF2.show
+--------+
| A|
+--------+
|£14326 |
|£1258634|
|£15626 |
|£163262 |
+--------+
+--------+
| A |
+--------+
|a14326 |
|c1258634|
|t15626 |
|f163262 |
+--------+
我想获得:
+--------+-------+
| A| B|
+--------+-------+
|£14326 | 14326|
|£1258634|1258634|
|£15626 | 15626|
|£163262 | 163262|
+--------+-------+
+--------+-------+
| A| B|
+--------+-------+
|a14326 |14326 |
|c1258634|1258634|
|t15626 |15626 |
|f163262 |163262 |
+--------+-------+
你有什么想法吗?
推荐答案
你可以这样做.
myDF1.show
+------+
| A|
+------+
|£14326|
|£12586|
|£15626|
|£16326|
+------+
myDF1.withColumn("B", expr("substring(A, 2, length(A))")).show
+------+-----+
| A| B|
+------+-----+
|£14326|14326|
|£12586|12586|
|£15626|15626|
|£16326|16326|
+------+-----+
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