scala，将运算符作为函数的参数传递 [英] scala, Passing an operator as argument of a function

问题描述

我有这个代码:

for( i <- 0 to 8){
  ((numbers(i) - i)/3).abs + ((numbers(i) - i)%3).abs
}

我想做，正如标题所说，这样的事情

and I would like to do, as the title says, something like this

for( i <- 0 to 8){
  by3(numbers(i), i, /) + by3(numbers(i), i, %)
}

def by3(a: Int, b: Int, op: Int => Int) = ((a - b) op 3).abs

并且可能还为此使用了部分应用函数..但是现在这可以实现吗?怎么样?

and probably also use a partially applied function for it.. but by now this would be possible to achieve? How?

推荐答案

要去掉下划线，您需要将函数定义为值.

To get rid of the underscores you need to define the functions as values.

val / = (a:Int, b: Int) => a / b
val % = (a:Int, b: Int) => a % b

def by3(a: Int, b: Int, fn: (Int, Int) => Int): Int = fn(a - b, 3).abs

(0 to 8).foreach(i => by3(numbers(i), i, /) + by3(numbers(i), i, %))

这篇关于scala，将运算符作为函数的参数传递的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！