在 Scala 中为方法调用选择某个超类 [英] Select certain super class for method call in Scala

问题描述

如果我在 Scala 中有这样一个类星座:

If I have a class constellation in Scala like this:

class A {
def foo() = "bar"
}

class B extends A {
override def foo() = "BAR"
}

class C extends B {
}

是否可以在类 C 中显式调用 A 中定义的方法 foo?

is it possible in class C to explicitly call the method foo that was defined in A?

推荐答案

不，你不能，因为它违反了封装.你绕过了你父母的行为，所以 C 应该扩展 B，但你绕过了这个.

No, you can't, because it violates encapsulation. You are bypassing your parents behaviour, so C is supposed to extend B, but you are bypassing this.

请参阅 Jon Skeets 对同一问题的出色回答 为什么是 super.super.method();在 Java 中不允许?.

Please see Jon Skeets excellent answer to the same question Why is super.super.method(); not allowed in Java?.

请注意，您可以通过反射访问该字段，但您不想这样做.

Please note that you can access the field by reflection, but you don't want to do that.

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