Java时间到正常格式 [英] Java time to the normal format

问题描述

我有 Java 时间 1380822000000.我想转换为我可以阅读的内容:

I have Java time 1380822000000. And I want to convert to something I can read:

import java.util.Date

object Ws1 {
  val a = new Date("1380822000000").toString()
}

导致异常

warning: there were 1 deprecation warning(s); re-run with -deprecation for detai
  ls
  java.lang.IllegalArgumentException
    at java.util.Date.parse(Date.java:615)
    at java.util.Date.<init>(Date.java:272)
    at .<init>(<console>:9)
    at .<clinit>(<console>)
    at .<init>(<console>:7)
    at .<clinit>(<console>)
    at $print(<console>)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57
  )
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl
  .java:43)
    at java.lang.reflect.Method.invoke(Method.java:606)
    at scala.tools.nsc.interpreter.IMain$ReadEvalPrint.call(IMain.scala:734)
    at scala.tools.nsc.interpreter.IMain$Request.loadAndRun(IMain.scala:983)
    at scala.tools.nsc.interpreter.IMain.loadAndRunReq$1(IMain.scala:573)
    at scala.tools.nsc.interpreter.IMain.interpret(IMain.scala:604)
    at scala.tools.nsc.interpreter.IMain.interpret(IMain.scala:568)
    at scala.tools.nsc.interpreter.ILoop.reallyInterpret$1(ILoop.scala:745)
    at scala.tools.nsc.interpreter.ILoop.interpretStartingWith(ILoop.scala:790)
    at scala.tools.nsc.interpreter.ILoop.command(ILoop.scala:702)
    at scala.tools.nsc.interpreter.ILoop.processLine$1(ILoop.scala:566)
    at scala.tools.nsc.interpreter.ILoop.innerLoop$1(ILoop.scala:573)
    at scala.tools.nsc.interpreter.ILoop.loop(ILoop.scala:576)
    at scala.tools.nsc.interpreter.ILoop$$anonfun$process$1.apply$mcZ$sp(ILoop.scal
  a:867)
    at scala.tools.nsc.interpreter.ILoop$$anonfun$process$1.apply(ILoop.scala:822)
    at scala.tools.nsc.interpreter.ILoop$$anonfun$process$1.apply(ILoop.scala:822)
    at scala.tools.nsc.util.ScalaClassLoader$.savingContextLoader(ScalaClassLoader.
  scala:135)
    at scala.tools.nsc.interpreter.ILoop.process(ILoop.scala:822)
    at org.jetbrains.plugins.scala.worksheet.WorksheetRunner.main(WorksheetRunner.j
  ava:66)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57
  )
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl
  .java:43)
    at java.lang.reflect.Method.invoke(Method.java:606)
    at com.intellij.rt.execution.application.AppMain.main(AppMain.java:120)

如何将其转换为正常的人类表示?

How do I convert it to the normal human representation?

推荐答案

或者做更好的事情并使用 org.jodatime;

Or do the better thing and use org.jodatime;

import org.joda.time.DateTime;

val timestamp = new DateTime(1380822000000L);

如您所见此处，自 EPOCH 已实施以来的几毫秒.

as you can see here, a miliseconds since EPOCH is already implemented.

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