将可变长度参数传递给另一个期望相同的函数? [英] Pass variable-length arguments to another function expecting the same?

问题描述

如何在 Scala 中正确编码?

How to code this right in Scala?

def myFun(strings: String*) = {
  // do something...
}

def myWraper(strings: String*) = {
  // do something else and then call myFun with the dame input
  myFun(strings)
}

我试过放一个星号

def myWraper(strings: String*) = {
  // do something else and then call myFun with the dame input
  myFun(strings*)
}

但这似乎不起作用...

But this doesn't seem to work...

推荐答案

试试这个:

 myFun(strings: _*)

您需要告诉它在可变参数中拆分 strings.

You need to tell it to split strings up across the varargs.

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