使用 RegexParsers 解析空白/空格 [英] Parsing a blank / whitespace with RegexParsers

问题描述

解析空白/空格有什么问题?

What is the problem with parsing the blank/whitespace?

scala> object BlankParser extends RegexParsers {
         def blank: Parser[Any] = " "
         def foo: Parser[Any] = "foo"
       }
defined module BlankParser

scala> BlankParser.parseAll(BlankParser.foo, "foo")
res15: BlankParser.ParseResult[Any] = [1.4] parsed: foo

scala> BlankParser.parseAll(BlankParser.blank, " ")
res16: BlankParser.ParseResult[Any] =
[1.2] failure: ` ' expected but ` ' found


 ^

scala>

推荐答案

scala 的词法分析器会丢弃空格.尝试覆盖 val skipWhitespace = false避免这种情况.

the lexer for scala throws blankspaces away. try override val skipWhitespace = false to avoid this.

问题已经解决了，所以看起来......用于嵌入在 html 中的语言的 Scala 解析器组合器或文本(如 php)

the question was already solved so it seems... Scala parser combinators for language embedded in html or text (like php)

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