使用带有指向字符的指针的 scanf 函数 [英] using scanf function with pointers to character

问题描述

我编写了以下代码.

int main(){
   char arrays[12];
   char *pointers;
   scanf("%s",arrays);
   scanf("%s",pointers);
   printf("%s",arrays);
   printf("%s",pointers);
   return 0;
}

为什么我写`scanf("%s",pointers)时会报错?

Why does it give an error when I write `scanf("%s",pointers)?

推荐答案

char *pointers; 

必须被初始化.你不能将字符串扫描到pointers，直到你将它指向某个地址.计算机需要知道在哪里存储从键盘读取的值.

must be initialized.You can not scan string into pointers until you point it to some address. The computer needs to know where to store the value it reads from key board.

int main(){
   char arrays[12];
   char *pointers= arrays;
   scanf("%s",pointers);
   printf("%s",pointers);
   return 0;
}

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