无法在 c 中使用 fscanf 读取整数 [英] Failed to read integer using fscanf in c

问题描述

FILE *fin = fopen("figura.in", "r");
if(fscanf(fin, "%d %d %d %d", &int[0], &int[1], &int[2], &int[3]) == 1)     {
        printf("%d\t%d\t%d\t%d\n", int[0], int[1], int[2], int[3]);
    } else {
        printf("failed to read integer.\n");
    }

我无法读取整数.该文件没问题，它由 4 个整数组成.怎么了?

I get failed to read integer. The file is okay, it consists 4 integers. What is wrong?

推荐答案

您应该检查 fscanf 是否返回 4，即格式字符串中的输入数量:

You should be checking to see if fscanf returns 4, the number of inputs in your format string:

if(fscanf(fin, "%d %d %d %d", &arr[0], &arr[1], &arr[2], &arr[3]) == 4) 

来自手册页:

返回成功匹配和分配的输入项的数量，可以少于提供的数量，或者在早期匹配失败的情况下甚至为零.

return the number of input items successfully matched and assigned, which can be fewer than provided for, or even zero in the event of an early matching failure.

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