逐行读取单词并将它们放在数组中 [英] Reading words in line and putting them in array

问题描述

我需要我的程序读取文件的一行，然后解析该行并将任何单词插入到每个数组的索引中.唯一的问题是我不知道每行有多少个单词，每行可以是1-6个单词.

I need my program to read a line of a file, and then parse the line and insert any words into an index of each array. The only problem is that I don't know how many words there are per line, it can be 1-6 words per line.

这就是一个简单文件的样子:

So this is what a simple file can look like:

苹果橙

电脑终端键盘鼠标

如果我扫描第 1 行，我需要一个字符数组来保存单词 apple 和 oranges.示例:

I would need a char array to hold the words apple and oranges if I am scanning line 1. Example:

words[0][0] = "apple";
words[1][0] = "oranges";

到目前为止，我有这样的东西，但我怎样才能使它在每行少于 6 个单词的情况下起作用?

So far, I have something like this, but how can I make it so it works with fewer than 6 words per line?

fscanf(file, "%19[^ ] %19[^ ] %19[^ ] %19[^ ] %19[^ ] %19[^ ]", string1, string2, string3, string4, string5, string6);

推荐答案

您正在阅读整个文件，而不是一行.

You are reading the entire file, not a line.

你可以这样做:

char line [128];
char *pch;
char words[6][20]; // 6 words, 20 characters 
int x;

while ( fgets ( line, sizeof line, file ) != NULL ) /* read a line */
      {
         pch = strtok (line," ,.-");
         while (pch != NULL)
         {
            strcpy(words[x], pch);
            pch = strtok (NULL, " ,.-");
         }
         x++;

        /*
           At this point, the array "words" has all the words in the line
         */

      }

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