运行计划任务后将计算机置于待机状态，但前提是必须唤醒才能运行它 [英] Put computer in standby after running a scheduled task but only if it had to wake up to run it

问题描述

我有一个计划任务，我想每隔几个小时运行一次.如果计算机当前处于待机状态，我希望它唤醒，运行任务，然后重新进入睡眠状态.如果计算机当前处于开启状态，我希望它运行任务但不重新进入睡眠状态，因为那会很烦人.

I have a scheduled task which I want to run every few hours. If the computer is currently in standby, I want it to wake up, run the task, then go back to sleep. If the computer is currently on, I want it to run the task but not go back to sleep, because that would be annoying.

有没有办法知道计划任务是否必须唤醒计算机才能运行?

Is there any way of knowing whether a scheduled task had to wake the computer to run?

推荐答案

我刚刚意识到一种方法是运行 powercfg -lastwake

I've just realised one way of doing it which is to run powercfg -lastwake

这是醒来运行任务时的输出:

This is the output when waking to run a task:

C:\Users\will>powercfg -lastwake
Wake History Count - 1
Wake History [0]
  Wake Source Count - 1
  Wake Source [0]
    Type: Wake Timer
    Owner: [SERVICE] \Device\HarddiskVolume5\Windows\System32\svchost.exe (Schedule)
    Owner Supplied Reason: Task Scheduler will execute '\test' task.

这是正常的输出:

C:\Users\will>powercfg -lastwake
Wake History Count - 1
Wake History [0]
  Wake Source Count - 1
  Wake Source [0]
    Type: Fixed Feature
    Power Button

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