两个查询MySQL的一个JSON对象 [英] Two queries mysql in one object json

问题描述

我有两个表，我想将它们转换为JSON是这样的：

I have two tables that I want to convert them to json like this:

[
   {
      "date":"2013-07-20",
      "id":"123456",
      "year":"2013",
      "people":[
         {
            "name":"First",
            "age":"60",
            "city":"1"
         },
         {
            "name":"second",
            "age":"40",
            "city":"2"
         },
         {
            "name":"third",
            "age":"36",
            "city":"1"
         }
      ]
   }
]

但我的code的结果是这样的：

but the result of my code is this:

[
   {
      "date":"2013-07-20",
      "id":"123456",
      "year":"2013",}
      ,{
      "people":[
         {
            "name":"First",
            "age":"60",
            "city":"1"
         },
         {
            "name":"second",
            "age":"40",
            "city":"2"
         },
         {
            "name":"third",
            "age":"36",
            "city":"1"
         }
      ]
   }
]

的 code创建一个新对象到阵列人，我想是在同一个对象

the code creates a new object to the array "people" and I want that are in the same object

$result = mysql_query("SELECT * FROM data where id='123456'");
$fetch = mysql_query("SELECT name,age,city FROM people where id='123456'"); 

$json = array();
$json2['people'] = array();

  while ($row = mysql_fetch_array($result, MYSQL_ASSOC)){
    $json[] = $row;
  }

  while ($row = mysql_fetch_assoc($fetch)){
    $row_temp["name"]=$row["name"];
    $row_temp["age"] = $row["age"];
    $row_temp["city"] = $row["city"];

   array_push($json2['people'],$row_temp);
   }

    array_push($json, $json2);

echo Json_encode($json);

数组如何我可以在同一个对象表数据？

How I can make the array is in the same object as the table "data"?

非常感谢

推荐答案

我觉得你可以试试这个

$result = mysql_query("SELECT * FROM data where id='123456'");
$fetch = mysql_query("SELECT name,age,city FROM people where id='123456'"); 

// I think, you'll get a single row, so no need to loop
$json = mysql_fetch_array($result, MYSQL_ASSOC);

$json2 = array();
while ($row = mysql_fetch_assoc($fetch)){
    $json2[] = array( 
        'name' => $row["name"],
        'age' => $row["age"],
        'city' => $row["city"]
    );
}
$json['people'] = $json2;
echo json_encode($json);

的print_r（$ JSON）的结果应该是这样的。

Array
(
    [date] => 2013-07-20
    [year] => 2013
    [id] => 123456
    [people] => Array
        (
            [0] => Array
                (
                    [name] => First
                    [age] => 60
                    [city] => 1
                )

            [1] => Array
                (
                    [name] => second
                    [age] => 40
                    [city] => 2
                )

        )

)

的结果回声json_en code（$ JSON）应

{
    "date" : "2013-07-20",
    "year":"2013",
    "id":"123456",
    "people":
    [
        {
            "name" : "First",
            "age" : "60",
            "city" : "1"
        },
        {
            "name" : "second",
            "age" : "40",
            "city" : "2"
        }
    ]
}

如果您回声json_en code（阵列（$ JSON））那么你会得到你的整个 JSON 包裹在一个阵列，像这样

If you do echo json_encode(array($json)) then you will get your whole json wrapped in an array, something like this

[
    {
        "date" : "2013-07-20",
        "year":"2013",
        "id":"123456",
        "people":
        [
            {
                "name" : "First",
                "age" : "60",
                "city" : "1"
            },
            {
                "name" : "second",
                "age" : "40",
                "city" : "2"
            }
        ]
    }
]

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