按时间戳绘制 numpy 数组的直方图 [英] plotting a histogram of a numpy array by timestamp
问题描述
我的数组有成对的 Unix 时间戳和值.
My array has pairs of unix timestamps and values.
[[ 1.40170249e+09 9.00000000e+01]
[ 1.40170249e+09 9.10000000e+01]
[ 1.40170249e+09 9.20000000e+01]
...,
[ 1.41149703e+09 1.09000000e+02]
[ 1.41149703e+09 1.06000000e+02]
[ 1.41149703e+09 1.06000000e+02]]
我设法用 pyplot.hist(array[:,1]); 绘制了整个第二列的直方图;pyplot.show()
.但我真正想做的是按天对 array[:,1]
进行分类(由数组 [:,0] 中的 unix 时间戳派生),并将它们绘制为堆叠直方图,每个(彩色)堆栈代表一天.这样做的最佳方法是什么?
I have managed to plot a histogram of the whole second column with pyplot.hist(array[:,1]); pyplot.show()
. But what I really want to do, is to bin array[:,1]
by day (as derived by the unix timestamps in array[:,0]), and plot these as a stacked histogram, with each (colored) stack representing a day. What might be the best way to do that?
推荐答案
既然你有一个 groupby
参与其中,那么使用 pandas
是有意义的:>
Since you have a groupby
involved in this, it will make sense to use pandas
:
In [192]:
import pandas as pd
import numpy as np
import time
A = np.array([[ 1.40170249e+09, 9.00000000e+01],
[ 1.40170249e+09, 9.10000000e+01],
[ 1.40170249e+09, 9.20000000e+01],
[ 1.41149703e+09, 1.09000000e+02],
[ 1.41149703e+09, 1.06000000e+02],
[ 1.41149703e+09, 1.06000000e+02]])
df = pd.DataFrame(A, columns=['date', 'val'])
df['date'] = df.date.map(lambda x: time.gmtime(x))
print df
date val
0 (2014, 6, 2, 9, 48, 10, 0, 153, 0) 90
1 (2014, 6, 2, 9, 48, 10, 0, 153, 0) 91
2 (2014, 6, 2, 9, 48, 10, 0, 153, 0) 92
3 (2014, 9, 23, 18, 30, 30, 1, 266, 0) 109
4 (2014, 9, 23, 18, 30, 30, 1, 266, 0) 106
5 (2014, 9, 23, 18, 30, 30, 1, 266, 0) 106
In [193]:
grp_obj = df.groupby(df.date.map(lambda x: time.strftime('%Y-%m-%d', x)))
plt.hist([value.val.values for grp, value in grp_obj],
stacked=True,
label=[grp for grp, value in grp_obj])
plt.legend()
Out[193]:
<matplotlib.legend.Legend at 0x10902d950>
而且您还需要按年-月-日对它们进行分组,以避免将不同月份/年份中的日期组合在一起.
And also you need to group them by year-month-day in order to avoid having days in different months/years grouped together.
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