scipy RegularGridInterpolator 维度 0 中的点必须严格升序 [英] scipy RegularGridInterpolator The points in dimension 0 must be strictly ascending

问题描述

调用时:

interpolator = scipy.interpolate.RegularGridInterpolator((X, Y, Z), data, method='linear')

我收到错误维度 0 中的点必须严格升序".

I get the error "The points in dimension 0 must be strictly ascending".

为什么点必须具有严格递增的 x 值?当然，我可以创建一个具有相同 x 值的数据的内插器，例如将坐标放入

Why must the points have strictly ascending x values? Surely I can create an interpolator with data with the same x values at time, for example with the coordinates into the data array of

0,0,0 和 0,0,1

0,0,0 and 0,0,1

(或 X = [0,0]，y = [0,0] 和 Z = [0,1]

(or X = [0,0], y = [0,0] and Z = [0,1]

我一定遗漏了一些关于输入格式的信息，但看不到什么.

I must be missing something about the input format, but can't see what.

推荐答案

好吧，看起来 RegularGridInterpolator 不是我需要的，因为它需要定义网格中的所有值.LinearNDInterpolator 正是我所需要的.

Ok, it looks like RegularGridInterpolator isn't what I need, because it requires all values in the grid to be defined. LinearNDInterpolator is what I need.

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