PHP：设置在一个单独的数组定义的使用路径多维关联数组元素的值 [英] PHP: Set the value of a multidimensional associative array element using a path defined in a separate array

问题描述

好了，所以我有一个包含以下元素的数组：

  $阵列['一'] ['B'] [0] ['C'];
$阵列['一'] ['B'] [1] ['C'];
$阵列['一'] ['D'] [0] ['C'] ['C'];
$数组['B'] ['C'];
 

然后在一个单独的阵列中，我定义的路径，这些值：

  $结构[0] =阵列（'A'，'B'，'＃'，'C'）;
$结构[1] =阵列（'一个'，'D'，'＃'，'C'，'C'）;
$结构[2] =阵列（'B'，'C'）;
 

最后，我有一个数组持有的值：

  $值[0] =阵列（'value0-0'，'value0-1'）;
$值[1] =阵列（'value1-0'）;
$值[2] =阵列（'value2-0'）;
 

我试图找到一个简单的功能/循环，将能够在$值应用值到在$结构中定义$数组的数组的路径。

最终的结果将是：

  $阵列['一'] ['B'] [0] ['C'] ='value0-0';
$阵列['一'] ['B'] [1] ['C'] ='value0-1';
$阵列['一'] ['D'] [0] ['C'] ['C'] ='value1-0';
$数组['B'] ['C'] ='value2-0';
 

在$ a的情况下的值[0]或$值[1]，这将是可以循环通过每个值和替代$结构元件匹配'＃'与该特定$值迭代次数。

这是简单地屈服于下来，写抽出递归函数的情况下，还是有一个聪明的构造或PHP函数，可以提供更好的解决方案？

解决方案：

感谢马里奥，我最终的解决办法是：

 的foreach（$结构作为$ I =＆GT; $键）
  的foreach（$值[$ i]为$ VAL）{
    $ R =安培; $阵列;    的foreach（$键为$键）{        如果（$键==＃）{$键= $ I; }        $ R =安培; $ R [$关键]; //移动指针指向子阵列
    }    $ R = $ VAL;
  }
}
 

解决方案

您将有引用工作遍历目标数组：

 函数注入（$数组$结构，$值）{    的foreach（$结构作为$ I =＆GT; $键）
    的foreach（$值[$ i]为$ VAL）{
        $ R =安培; $阵列;        的foreach（$键为$键）{            如果（$键==＃）{$键=计数（$ R）; }            的setType（$ R [$键]，数组）;
            $ R =安培; $ R [$关键]; //移动指针指向子阵列
        }        $ R = $ VAL;
    }
 

Ok so I have an array that holds the following elements:

$array['a']['b'][0]['c'];
$array['a']['b'][1]['c'];
$array['a']['d'][0]['c']['c'];
$array['b']['c'];

Then in a separate array, I have defined the path to these values:

$structure[0] = array('a','b','#','c');
$structure[1] = array('a','d','#','c','c');
$structure[2] = array('b','c');

Finally, I have an array holding the values:

$values[0] = array('value0-0','value0-1');
$values[1] = array('value1-0');
$values[2] = array('value2-0');

I'm trying to find a simple function/loop that will be able to apply the values in $values to the array path of $array that is defined in $structure.

The end result would be:

$array['a']['b'][0]['c']='value0-0';
$array['a']['b'][1]['c']='value0-1';
$array['a']['d'][0]['c']['c']='value1-0';
$array['b']['c']='value2-0';

In the case of $values[0] or $values[1], it would be able to loop through each value and substitute the $structure element matching '#' with the iteration number for that particular $value.

Is this simply a case of knuckling down and writing a drawn out recursive function, or is there a smart construct or php function that could provide a more elegant solution?

SOLUTION:

Thanks to Mario, my eventual solution is:

foreach ($struct as $i=>$keys)
  foreach ($values[$i] as $val) {
    $r = & $array;

    foreach ($keys as $key) {

        if ($key == "#") { $key = $i; }

        $r = & $r[$key];    // move pointer to subarray
    }

    $r = $val;
  }
}

解决方案

You will have to work with references to traverse the target array:

function inject($array, $struct, $values) {

    foreach ($struct as $i=>$keys)
    foreach ($values[$i] as $val) {
        $r = & $array;

        foreach ($keys as $key) {

            if ($key == "#") { $key = count($r); }

            settype($r[$key], "array");
            $r = & $r[$key];    // move pointer to subarray
        }

        $r = $val;
    }

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