如何为 Seaborn Facet Plot 添加标题 [英] How to add a title to Seaborn Facet Plot

问题描述

如何为这个 Seaborne 情节添加标题?让我们给它一个标题我是一个头衔".

How do I add a title to this Seaborne plot? Let's give it a title 'I AM A TITLE'.

tips = sns.load_dataset("tips")
g = sns.FacetGrid(tips, col="sex", row="smoker", margin_titles=True)
g.map(sns.plt.scatter, "total_bill", "tip")

推荐答案

稍微更新，使用 seaborn 0.11.1:

Updating slightly, with seaborn 0.11.1:

Seaborn 的 relplot 函数创建一个 FacetGrid 并为每个子图提供自己的解释性标题:

Seaborn's relplot function creates a FacetGrid and gives each subplot its own explanatory title:

import seaborn as sns
tips = sns.load_dataset('tips')

rp = sns.relplot(data=tips, x='total_bill', y='tip',
                 col='sex', row='smoker',
                 kind='scatter')
# rp is a FacetGrid; 
# relplot is a nice organized way to use it

rp.fig.subplots_adjust(top=0.9) # adjust the Figure in rp
rp.fig.suptitle('ONE TITLE FOR ALL')

如果直接创建 FacetGrid，就像在原始示例中一样，您将获得列和行标签，而不是单独的子图标签:

If you create the FacetGrid directly, as in the original example, you get column and row labels instead of individual subplot labels:

from matplotlib.pyplot import scatter as plt_scatter
g = sns.FacetGrid(tips, col='sex', row='smoker', 
                  margin_titles=True)
g.map(plt_scatter, 'total_bill', 'tip')
g.fig.subplots_adjust(top=0.9)
g.fig.suptitle('TITLE!')

FacetGrid 对象是使用 matplotlib Figure 对象构建的，因此我们可以使用通常从 matplotlib 中熟悉的 subplots_adjust、suptitle.

The FacetGrid objects are built with matplotlib Figure objects, so we can use subplots_adjust, suptitle that may be familiar from matplotlib in general.

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