提取单词前后字符串的一部分 [英] extract part of a string before and after a word

问题描述

我需要提取并显示一些词before和after一个查询词，比如谷歌搜索结果，例如:

i need to extract and show some words before and after a query word, something like google search results, for example:

$str = "hi user! welcome to new php open source world, we are trying to learn you something!";
$query = "new php";
$result = "... welcome to new php open source ...";

我在 google 上搜索了一个 SO，但没有找到明确的答案，或者我的 php 知识还不够！是否有可行且易于使用的功能来完成这项工作?

i searched google an SO but didn't find a clear answer or maybe my php knowledge was not enough! is there a workable and easy-to-use function to do this job?

推荐答案

function yourFuncName($str, $query, $numOfWordToAdd) {
    list($before, $after) = explode($query, $str);

    $before = rtrim($before);
    $after  = ltrim($after);

    $beforeArray = array_reverse(explode(" ", $before));
    $afterArray  = explode(" ", $after);

    $countBeforeArray = count($beforeArray);
    $countAfterArray  = count($afterArray);

    $beforeString = "";
    if($countBeforeArray < $numOfWordToAdd) {
        $beforeString = implode(' ', $beforeArray);
    }
    else {
        for($i = 0; $i < $numOfWordToAdd; $i++) {
            $beforeString = $beforeArray[$i] . ' ' . $beforeString; 
        }
    }

    $afterString = "";
    if($countAfterArray < $numOfWordToAdd) {
        $afterString = implode(' ', $afterArray);
    }
    else {
        for($i = 0; $i < $numOfWordToAdd; $i++) {
            $afterString = $afterString . $afterArray[$i] . ' '; 
        }
    }

    $string = $beforeString . $query . ' ' . $afterString;

    return $string;
}

输出是: user!欢迎来到新的 php 开源世界， ($numOfWordToAdd = 3)

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