Java的字符数组 - 删除元素 [英] Java char Array - deleting elements

问题描述

在Java中，我想从一个字符数组删除某些元素，因此它确实是这样的：

In Java, I want to delete certain elements from a char array so it does something like:

char[] Array1 = {'h','m','l','e','l','l'};
Array1 = //character index[2] to character index[5]

如何才能做到这一点？

How can this be done?

推荐答案

在Java中，你不能删除一个数组元素。但是，你可以：

In Java you can't delete elements from an array. But you can either:

创建一个新的的char [] 复制只有你想保留的元素;为此，你可以使用<一个href=\"http://docs.oracle.com/javase/6/docs/api/java/lang/System.html#arraycopy%28java.lang.Object,%20int,%20java.lang.Object,%20int,%20int%29\"相对=nofollow> System.arraycopy（） 或更简单的<一个href=\"http://docs.oracle.com/javase/6/docs/api/java/util/Arrays.html#copyOfRange%28char%5b%5d,%20int,%20int%29\"相对=nofollow> Arrays.copyOfRange（） 。例如，对于只复制数组的前三个字母：

Create a new char[] copying only the elements you want to keep; for this you could use System.arraycopy() or even simplerArrays.copyOfRange(). For example, for copying only the first three characters of an array:

char[] array1 = {'h','m','l','e','l','l'};
char[] array2 = Arrays.copyOfRange(array1, 0, 3);

或者使用列表与LT;性格＆GT; ，它可以让你获得一个子列表与一系列的元素：

Or use a List<Character>, which allows you to obtain a sublist with a range of elements:

List<Character> list1 = Arrays.asList('h','m','l','e','l','l');
List<Character> list2 = list1.subList(0, 3);

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