正则表达式从字符串中提取版本 [英] Regex to extract version from string

问题描述

我有一个低于值的字符串

I have a string which has below value

String1=winos-app-1.2.0-4.20120308.InLinuxOS.x86_64

String1=winos-app-1.2.0-4.20120308.InLinuxOS.x86_64

我只需要从这个字符串中提取1.2.0-4"的版本

I need to extract only version from this string which is "1.2.0-4"

我已经用 sed 尝试过如下所述的正则表达式

I have tried regular expression as mentioned below with sed

sed -ne 's/[^0-9]*\(\([0-9]\.\)\{0,1\}[0-9][^.]\).*/\1/p'

但我只得到结果1.2.0-"，-"后缺少数字，即 4.我尝试更正它，但它返回空值.

but I am only getting result "1.2.0-", missing number after "-" which is 4. I tried correcting it but it is returning null.

请多多指教

推荐答案

sed -n 's/^.*-\([0-9.]*-[0-9]*\)\..*$/\1/p'

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