localtime() 中的 malloc() 段错误? [英] malloc() seg fault in localtime()?

问题描述

这是 ny 堆栈

malloc() at 0xb7dfd333  
strdup() at 0xb7e01866  
tzset_internal() at 0xb7e2ef68  
__tz_convert() at 0xb7e2f26a    
localtime() at 0xb7e2d901   
Send_Trace() at my_trace.c:265 0x8053373    

这是有问题的代码..

and here's the offending code ..

void Send_Trace(const char const *Trace_Text, ...)
{
   time_t time_now = time(NULL);
   tm = *localtime(&time_now);

它通常工作正常，但偶尔会抛出上面显示的段错误.

It is generally working fine, but occassionally throws the seg fault shown above.

有什么想法吗?

推荐答案

有什么想法吗?

malloc 或 free 中的任何崩溃在 99.999% 的情况下都是其他地方早期堆损坏的结果.

Any crash inside malloc or free is in 99.999% of cases the result of earlier heap corruption elsewhere.

可能导致 malloc 后续崩溃的堆损坏示例:在未分配的内存上调用 free，在某些内存上调用 free两次指针，上溢或下溢堆分配的缓冲区，等等.

Examples of heap corruption which could lead to subsequent crash in malloc: calling free on a non-allocated memory, calling free on some pointer twice, overflowing or underflowing a heap-allocated buffer, etc. etc.

查找此类错误的最快方法是:valgrind(如果在您的平台上可用)或 AddressSanitizer(在 Clang 和 GCC 的最新版本中实现).

The fastest way to find such bugs are: valgrind (if available on your platform), or AddressSanitizer (implemented in recent versions of Clang and GCC).

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