如何解决我的登录/创建帐户程序中的这个序列化错误? [英] How do I solve this serialization error on my log in/create account program?

问题描述

我正在编写一个简单的 GUI 程序，它使用来自文本文件的登录信息.它从另一个创建用户帐户的 GUI 程序获取登录信息.我不确定如何轻松有效地序列化它，因为这只是我最近学到的东西.我应该怎么办?我如何解决这个序列化错误，我可以做些什么来改进它并使其正常运行.

I'm writing a simple GUI program that uses log in information from a text file. It takes log in info from another GUI program that create's user accounts. I'm not sure how to easily serialize this effectively, as it's only something that I've learned recently. What should I do? How do I solve this serialization error, and what can I do to improve it and make it functional.

用户类别:

package passwordProgram;

import java.util.ArrayList;
import java.util.Arrays;

import java.awt.BorderLayout;
import java.awt.Color;
import java.awt.GridBagConstraints;
import java.awt.GridBagLayout;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;

import java.io.Serializable;

import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JLabel;
import javax.swing.JPanel;
import javax.swing.JPasswordField;
import javax.swing.JTextField;
import javax.swing.UIManager;

public class User implements Serializable, ActionListener {

    public static ArrayList<String> allUsernames = new ArrayList<String>();

    String username;
    String password;

    public static void main(String[] args) {
        try {
            UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
        } catch (Exception e) {
            e.printStackTrace();
        }
        User user = new User();
        user.mainGUI();
    }



    JFrame frame;
    JPanel panel;
    JTextField createUsername;
    JPasswordField createPassword;
    JPasswordField confirmPassword;
    JButton createAccount;
    JLabel noValid;

    public void mainGUI() {
        noValid = new JLabel();
        frame = new JFrame("Create a new account!");
        panel = new JPanel();
        panel.setBackground(Color.ORANGE);
        createPassword = new JPasswordField(10);
        confirmPassword = new JPasswordField(10);
        createUsername = new JTextField(10);
        JLabel userTxt = new JLabel("New Username: ");
        JLabel userPass = new JLabel("New Password: ");
        JLabel confirmPass = new JLabel("Confirm Password: ");
        createAccount = new JButton("Create your account!");

        panel.setLayout(new GridBagLayout());
        GridBagConstraints left = new GridBagConstraints();
        left.anchor = GridBagConstraints.WEST;
        GridBagConstraints right = new GridBagConstraints();
        right.anchor = GridBagConstraints.EAST;
        right.weightx = 2.0;
        right.fill = GridBagConstraints.HORIZONTAL;
        right.gridwidth = GridBagConstraints.REMAINDER;

        frame.getContentPane().add(BorderLayout.NORTH, noValid);
        frame.getContentPane().add(BorderLayout.CENTER, panel);
        panel.add(userTxt, left);
        panel.add(createUsername, right);
        panel.add(userPass, left);
        panel.add(createPassword, right);
        panel.add(confirmPass, left);
        panel.add(confirmPassword, right);

        frame.getContentPane().add(BorderLayout.SOUTH, createAccount);
        frame.setVisible(true);
        frame.setSize(500, 300);

        createAccount.addActionListener(this);
    }

    public void actionPerformed(ActionEvent event) {
        if (createUsername.getText().length() <= 0 ) {
            noValid.setText("That is not a valid username. Please try again.");
            frame.getContentPane().add(BorderLayout.NORTH, noValid);
        }

        else if (allUsernames.contains(createUsername.getText())) {
            noValid.setText("That username is already taken. Please try again.");
            frame.getContentPane().add(BorderLayout.NORTH, noValid);
        }

        else if (!(Arrays.equals(createPassword.getPassword(), confirmPassword.getPassword()))) {
            noValid.setText("Your passwords do not match!");
            frame.getContentPane().add(BorderLayout.NORTH, noValid);
        } else {    
            SaveUser sUser = new SaveUser();
            sUser.createAccount(this);
            noValid.setText("Account created successfully");
            frame.getContentPane().add(BorderLayout.NORTH, noValid);
        }
    }
}

SaveUser 类(序列化)

SaveUser class(serialization)

package passwordProgram;

import java.io.FileOutputStream;
import java.io.ObjectOutputStream;
import java.io.Serializable;

public class SaveUser implements Serializable{
    public void createAccount(User u) {
        try {
            FileOutputStream fileOS = new FileOutputStream("userInfo.ser");
            ObjectOutputStream objectOS = new ObjectOutputStream(fileOS);
            objectOS.writeObject(u);
            objectOS.close();
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

这是我尝试运行 User 类时遇到的错误.

Here's the error I get when I try and run the User class.

java.io.NotSerializableException: passwordProgram.User
    at java.io.ObjectOutputStream.writeObject0(Unknown Source)
    at java.io.ObjectOutputStream.writeObject(Unknown Source)
    at passwordProgram.SaveUser.createAccount(SaveUser.java:12)
    at passwordProgram.User.actionPerformed(User.java:104)
    at javax.swing.AbstractButton.fireActionPerformed(Unknown Source)
    at javax.swing.AbstractButton$Handler.actionPerformed(Unknown Source)
    at javax.swing.DefaultButtonModel.fireActionPerformed(Unknown Source)
    at javax.swing.DefaultButtonModel.setPressed(Unknown Source)
    at javax.swing.AbstractButton.doClick(Unknown Source)
    at javax.swing.plaf.basic.BasicRootPaneUI$Actions.actionPerformed(Unknown Source)
    at javax.swing.SwingUtilities.notifyAction(Unknown Source)
    at javax.swing.JComponent.processKeyBinding(Unknown Source)
    at javax.swing.KeyboardManager.fireBinding(Unknown Source)
    at javax.swing.KeyboardManager.fireKeyboardAction(Unknown Source)
    at javax.swing.JComponent.processKeyBindingsForAllComponents(Unknown Source)
    at javax.swing.JComponent.processKeyBindings(Unknown Source)
    at javax.swing.JComponent.processKeyEvent(Unknown Source)
    at java.awt.Component.processEvent(Unknown Source)
    at java.awt.Container.processEvent(Unknown Source)
    at java.awt.Component.dispatchEventImpl(Unknown Source)
    at java.awt.Container.dispatchEventImpl(Unknown Source)
    at java.awt.Component.dispatchEvent(Unknown Source)
    at java.awt.KeyboardFocusManager.redispatchEvent(Unknown Source)
    at java.awt.DefaultKeyboardFocusManager.dispatchKeyEvent(Unknown Source)
    at java.awt.DefaultKeyboardFocusManager.preDispatchKeyEvent(Unknown Source)
    at java.awt.DefaultKeyboardFocusManager.typeAheadAssertions(Unknown Source)
    at java.awt.DefaultKeyboardFocusManager.dispatchEvent(Unknown Source)
    at java.awt.Component.dispatchEventImpl(Unknown Source)
    at java.awt.Container.dispatchEventImpl(Unknown Source)
    at java.awt.Window.dispatchEventImpl(Unknown Source)
    at java.awt.Component.dispatchEvent(Unknown Source)
    at java.awt.EventQueue.dispatchEventImpl(Unknown Source)
    at java.awt.EventQueue.access$000(Unknown Source)
    at java.awt.EventQueue$3.run(Unknown Source)
    at java.awt.EventQueue$3.run(Unknown Source)
    at java.security.AccessController.doPrivileged(Native Method)
    at java.security.ProtectionDomain$1.doIntersectionPrivilege(Unknown Source)
    at java.security.ProtectionDomain$1.doIntersectionPrivilege(Unknown Source)
    at java.awt.EventQueue$4.run(Unknown Source)
    at java.awt.EventQueue$4.run(Unknown Source)
    at java.security.AccessController.doPrivileged(Native Method)
    at java.security.ProtectionDomain$1.doIntersectionPrivilege(Unknown Source)
    at java.awt.EventQueue.dispatchEvent(Unknown Source)
    at java.awt.EventDispatchThread.pumpOneEventForFilters(Unknown Source)
    at java.awt.EventDispatchThread.pumpEventsForFilter(Unknown Source)
    at java.awt.EventDispatchThread.pumpEventsForHierarchy(Unknown Source)
    at java.awt.EventDispatchThread.pumpEvents(Unknown Source)
    at java.awt.EventDispatchThread.pumpEvents(Unknown Source)
    at java.awt.EventDispatchThread.run(Unknown Source)

这是我在课堂上的登录:

And here's my log in class:

打包密码程序；

import java.awt.BorderLayout;
import java.awt.Color;
import java.awt.GridBagConstraints;
import java.awt.GridBagLayout;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.io.FileInputStream;
import java.io.ObjectInputStream;

import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JLabel;
import javax.swing.JPanel;
import javax.swing.JPasswordField;
import javax.swing.JTextField;
import javax.swing.UIManager;


public class LogInScreen implements ActionListener {


    public static void main(String[] args) {
        try {
        UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
        } 
        catch (Exception e) {
        }
        LogInScreen logger = new LogInScreen();
        logger.start();
    }

推荐答案

就我个人而言，我认为对象序列化在这种情况下已经结束了.

Personally, I think Object serialization is over kill in this situation.

您可以简单地将详细信息写入文本文件...

You could simply write the details to a text file...

public TestFileIO() {
    try {
        writeUser(new File("User.inf"), "Test", "Password".toCharArray());
    } catch (IOException ex) {
        ex.printStackTrace();
    }
}

public void writeUser(File file, String name, char[] password) throws IOException {
    BufferedWriter bw = null;
    try {
        bw = new BufferedWriter(new FileWriter(file));
        bw.write(name);
        bw.newLine();
        bw.write(password);
        bw.flush();
    } finally {
        try {
            bw.close();
        } catch (Exception e) {
        }
    }
}

这将简单地将用户名和密码写入文件，并用新行分隔.

This will simply write the user name and password to a file, separating each by a new line.

如果您在文件中需要多个用户，您可以使用预定义的分隔符将用户名密码简单地写在同一行...

If you need more then one user in the file, you could simple write the user name password on the same line, using a predefined delimiter...

public TestFileIO() {
    try {
        writeUser(new File("User.inf"), "Test", "Password".toCharArray());
    } catch (IOException ex) {
        ex.printStackTrace();
    }
}

public void writeUser(File file, String name, char[] password) throws IOException {
    BufferedWriter bw = null;
    try {
        bw = new BufferedWriter(new FileWriter(file));
        bw.write(name);
        bw.write(";");
        bw.write(password);
        bw.flush();
    } finally {
        try {
            bw.close();
        } catch (Exception e) {
        }
    }
}

现在，如果您担心将密码保存为纯文本，您可以(以及个人世界)将密码保存为 MD5 哈希...

Now, if you worried about saving the password as plain text, you could (and personally world) save the password as a MD5 hash...

public TestFileIO() {
    try {
        writeUser(new File("User.inf"), "Test", "Password".toCharArray());
    } catch (Exception ex) {
        ex.printStackTrace();
    }
}

public void writeUser(File file, String name, char[] password) throws IOException, NoSuchAlgorithmException {

    BufferedWriter bw = null;

    try {
        MessageDigest md = MessageDigest.getInstance("MD5");
        byte[] bytes = new byte[password.length];
        for (int i = 0; i < bytes.length; i++) {
            bytes[i] = (byte) password[i];
        }
        md.update(bytes);
        byte[] mdbytes = md.digest();

        StringBuffer sb = new StringBuffer();
        for (int i = 0; i < mdbytes.length; i++) {
            sb.append(Integer.toString((mdbytes[i] & 0xff) + 0x100, 16).substring(1));
        }

        bw = new BufferedWriter(new FileWriter(file));
        bw.write(name);
        bw.newLine();
        bw.write(sb.toString());
        bw.flush();
    } finally {
        try {
            bw.close();
        } catch (Exception e) {
        }
    }
}

这篇关于如何解决我的登录/创建帐户程序中的这个序列化错误?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！