合并在一个阵列中的红宝石两个数组的只有各元素 [英] Merging only respective elements of two arrays in one array in ruby

问题描述

您好我有红宝石以下两个数组

Hello I have the following two arrays in ruby

A=["a","b","c"]
B=["d","e","f"]

和我想生产这种

C = ["ad", "be", "cf"]

无论数组的长度。两个数组都是一样的长度，但。

regardless of array length. The two arrays are always the same length though.

有一个整洁的方式做到这一点？我的意思，而不是通过阵列，一个迭代循环。

Is there a neat way to do this? I mean instead of iterating through the arrays with a for loop.

推荐答案

与方法很简单的 阵列＃拉链 和的 阵列＃地图 ：

Very simple with the method Array#zip and Array#map :

A = ["a","b","c"]
B = ["d","e","f"]
A.zip(B).map { |a| a.join }
# => ["ad", "be", "cf"]
# or
A.zip(B).map(&:join)
# => ["ad", "be", "cf"]

另一种方式（但不是很好看）： - ）

One more way ( but not looks good ), :-)

A.map.with_index { |e,i| e + B[i] }
# => ["ad", "be", "cf"]

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