SESSION 无法检查登录 [英] SESSION is not working to check login

问题描述

你能告诉我这有什么问题吗?我非常确定这段代码是完全正确的，但我不知道为什么它在 Dreamweaver 和 netbean 等 Web 应用程序中的第 2 页看起来是错误的.

could you tell me what's wrong with this? I'm very sure this code is totally correct, but I've no idea why it looks like wrong at page 2 in web application like dreamweaver and netbean.

1.    session_start();
2.    if (isset($_SESSION['username'] == 1) && isset ($_SESSION['username']) == 'admin') {
3.     echo "<p> HELLO </p>";
4.    }

而且我必须让你知道这段代码真的像这样工作.

And I have to let you know that this code is really working something like this.

1.    session_start();
2.    if (isset ($_SESSION['username']) == 'admin') {
3.     echo "<p> HELLO </p>";
4.    }

你能指出上面遗漏了什么吗?

Can you point it out what's missing above?

推荐答案

isset() 仅在设置了变量时返回 true 或 false.因此，您实际上是在尝试比较 (true == 'admin') 或 (false == 'admin') ，这完全没有意义.

isset() only returns true or false if the variable was set. Therefore, you are actually trying to compare (true == 'admin') or (false == 'admin'), which makes no sense at all.

您首先需要确保设置了变量，然后将其值与 admin 进行比较.

What you need is first to make sure that the variable is set AND then compare its value to admin.

您需要将逻辑更改为:

   session_start();
   if (isset($_SESSION['username']) && ($_SESSION['username'] === 'admin')) {
    echo "<p> HELLO </p>";
   }

其他的也一样.

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