如何在 php 中获取会话 ID 或用户名? [英] How Can I get a Session Id or username in php?
问题描述
我有一个用户可以登录的网站.我尝试过:
I have a website where users can log in. I have tried:
<?php echo $_SESSION ['userlogin']
当用户登录时,我将他们的会话设置为用户登录,但不会显示他们的用户名.
这是我用的教程
and When users login I set their session as userlogin, but it won't show their username.
This is the tutorial I used
推荐答案
您是否开始会话 使用前?
所以要设置它:
<?php
//Fetch the username from the database
//The $login and $password I use here are examples. You should substitute this
//query with one that matches your needs and variables.
//On top of that I ASSUMED you are storing your passwords MD5 encrypted. If not,
//simply remove the md5() function from below.
$query = "SELECT name FROM users WHERE login='" . mysql_real_escape_string($login) . "' AND password='" . md5($password) . "'";
$result = mysql_query($query);
//Check if any row was returned. If so, fetch the name from that row
if (mysql_num_rows($result) == 1) {
$row = mysql_fetch_assoc_assoc($result);
$name = $row['name'];
//Start your session
session_start();
//Store the name in the session
$_SESSION['userlogin'] = $name;
}
else {
echo "The combination of the login and password do not match".
}
?>
并在另一个页面上检索它:
And to retrieve it on another page do:
<?php
//Start your session
session_start();
//Read your session (if it is set)
if (isset($_SESSION['userlogin']))
echo $_SESSION['userlogin'];
?>
编辑
有关如何创建登录表单的更多信息.您说您尝试设置 $_SESSION['user']
但这不起作用.
Some more information about how to create a loginform.. You say you tried setting $_SESSION['user']
but that this didn't work.
因此,请确保在此之前您确实执行了 session_start();
.如果你这样做了,一切都应该有效.除非您为会话分配一个空变量.因此,请仔细检查您分配的变量是否确实包含一个值.喜欢:
So just make sure that you actually did a session_start();
before that. If you did, everything should work. Unless you assign an empty variable to the session. So doublecheck that the variable you assign actually contains a value. Like:
<?php
session_start();
echo "Assigning session value to: " . $user;
$_SESSION['user'] = $user;
?>
在您将我链接到他们正在做的教程中:
In the tutorial you linked me to they are doing:
$_SESSION[user]=$_GET[userlogin];
这意味着他们正在分配一个从他们在此处创建的登录表单中获得的值:
This means they are assigning a value they got from their loginform that they create here:
function loginform() {
print "please enter your login information to proceed with our site";
print ("<table border='2'><tr><td>username</td><td><input type='text' name='userlogin' size'20'></td></tr><tr><td>password</td><td><input type='password' name='password' size'20'></td></tr></table>");
print "<input type='submit' >";
print "<h3><a href='registerform.php'>register now!</a></h3>";
}
您会看到 .但是这个表单周围没有
标签..所以这不会正确发布.所以你应该做的是:
There you see <input type='text' name='userlogin' size'20'>
. But there is no <form></form>
tag around this form.. So this won't properly post. So what you should do is the following:
<form method="POST" action="index.php">
<label for="userlogin">Username:</label> <input type="text" id="userlogin" name="userlogin" size="20" />
<label for="password">Password:</label> <input type="password" id="password" name="password" size="20" />
<input type="submit" value="login" />
</form>
此表单将使用 userlogin 和 password 作为 $_POST
变量将表单发送回 index.php.
This form will post the form back to index.php with userlogin and password as $_POST
variables.
在您的 index.php 中,您可以执行以下操作:
In your index.php you can then do:
<?php
//Get variables:
$login = mysql_real_escape_string($_POST['userlogin']);
$pass = mysql_real_escape_string($_POST['password']);
//Check your table:
$query = "SELECT userlogin FROM users WHERE userlogin = '" . $login . "' AND password='" . $pass . "'";
$result = mysql_query($query);
//Check if this user exists:
if (mysql_num_rows($result) == 1) {
echo "User exists!";
//Store the login in the session:
session_start();
$_SESSION['userlogin'] = $login;
}
else {
echo "Unknown user";
}
?>
如果不为您编写整个代码,我无法说得更清楚.所以我希望这对你有帮助.
I can't make it much clearer without writing the entire code for you. So I hope this helps you.
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