填写在C＃中的数组 [英] fill an array in C#

问题描述

在Java中有大约18静态补在类阵列服务于一个值赋给数组中的每个元素的方法。我在寻找一个相当于C＃来达到同样的事情，但我没有找到使用相同的紧凑什么：

1）的ForEach我了解按值传递数组中的元素，所以我不能改变他们

2）可枚举重复创建新的数组，这似乎是开销来创建一个新的数组，然后每个元素从数组复制

3）for循环不是pretty，我猜就是为什么Java的乡亲介绍了这款紧凑型符号开始以

4）从Array类的清除方法可以设置一切为零，但我怎么转换零到非零值我想要什么？

要演示Java的语法考虑这个code，打印三倍的数字7：

  INT [] III = {1，2，3};
Arrays.fill（三，7）;
对于（INT I：III）{
    的System.out.println（ⅰ）;
}
 

解决方案

编写自己的扩展方法

 公共静态类ArrayExtensions {
    公共静态无效的填充和LT; T＆GT;（这件T [] originalArray，T带）{
        的for（int i = 0; I＆LT; originalArray.Length;我++）{
            originalArray [I] =用;
        }
    }
}
 

和使用它像

  INT为foo [] =新INT [] {0,0,0,0,0};
foo.Fill（13）;
 

将填补所有的元素以13

In Java there are about 18 a static "fill" methods in the class Arrays that serve to assign one value to each element in an array. I'm looking for an equivalent in C# to achieve the same thing but I'm not finding anything with the same compactness:

1) ForEach as I understand passes elements in the array by value so I can't change them

2) Repeat from Enumerable creates a new array, it seems to be overhead to create a new array and then copy each element from the array

3) a for-loop isn't pretty, which I guess is why the Java folks introduced this compact notation to begin with

4) The Clear method from the Array class can set everything to zero, but then how do I convert zero to the non-zero value I want?

To demonstrate Java's syntax consider this code that prints three times the number 7:

int[] iii = {1, 2, 3};
Arrays.fill(iii, 7);
for (int i : iii) {
    System.out.println(i);
}

解决方案

Write yourself an extension method

public static class ArrayExtensions {
    public static void Fill<T>(this T[] originalArray, T with) {
        for(int i = 0; i < originalArray.Length; i++){
            originalArray[i] = with;
        }
    }  
}

and use it like

int foo[] = new int[]{0,0,0,0,0};
foo.Fill(13);

will fill all the elements with 13

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