Shell命令对整数求和，每行一个? [英] Shell command to sum integers, one per line?

问题描述

我正在寻找一个可以接受(作为输入)多行文本的命令，每行包含一个整数，并输出这些整数的总和.

I am looking for a command that will accept (as input) multiple lines of text, each line containing a single integer, and output the sum of these integers.

作为一点背景知识，我有一个日志文件，其中包括计时测量.通过搜索相关行和一些 sed 重新格式化，我可以列出该文件中的所有时间.我想算出总数.我可以将此中间输出通过管道传输到任何命令，以便进行最终求和.过去我一直使用 expr，但除非它在 ​​RPN 模式下运行，否则我认为它无法解决这个问题(即使那样也会很棘手).

As a bit of background, I have a log file which includes timing measurements. Through grepping for the relevant lines and a bit of sed reformatting I can list all of the timings in that file. I would like to work out the total. I can pipe this intermediate output to any command in order to do the final sum. I have always used expr in the past, but unless it runs in RPN mode I do not think it is going to cope with this (and even then it would be tricky).

如何得到整数的总和?

推荐答案

awk 应该怎么做?

Bit of awk should do it?

awk '{s+=$1} END {print s}' mydatafile

注意:如果您要添加超过 2^31 (2147483647) 的任何内容，某些版本的 awk 会有一些奇怪的行为.有关更多背景，请参阅评论.一种建议是使用 printf 而不是 print:

Note: some versions of awk have some odd behaviours if you are going to be adding anything exceeding 2^31 (2147483647). See comments for more background. One suggestion is to use printf rather than print:

awk '{s+=$1} END {printf "%.0f", s}' mydatafile

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