如何使用 Spring Boot 在类路径上首先放置目录? [英] How to put a directory first on the classpath with Spring Boot?

问题描述

我正在使用 Maven 构建我的 Spring Boot 应用程序，因此我可以使用以下命令启动它:

I am building my Spring Boot application using Maven, so I can start it with:

java -jar myjar-1.0-SNAPSHOT.jar --spring.profiles.active=prod

我想首先在类路径上有一个目录，这样我就可以在文件系统上放置一些文件，而无需解压缩 jar 来更改它们.

I want to have a directory first on the classpath that would allow me to place some files on the filesystem without having to unzip the jar to change them.

我曾尝试使用 loader.path，但它似乎不起作用.

I have tried using loader.path, but it does not seem to work.

java -Dloader.path="config/*" -jar myjar-1.0-SNAPSHOT.jar --spring.profiles.active=prod

config 目录是 jar 所在的子目录.我正在尝试加载一个密钥库文件，该文件在我的应用程序中作为 Resource 注入.src/main/resources 中有这样一个文件，但它只在我的 IDE 中有效，在打包为 jar 时无效.所以我想把一个文件放在类路径的第一个，以便在类路径中最先找到那个文件.

The config dir is a subdirectory of where the jar is located. I am trying to load a keystore file which is injected as a Resource in my application. There is such a file in the src/main/resources, but that only works in my IDE, not when packaged as a jar. So I want to put a file first on the classpath so that that one is found first on the classpath.

推荐答案

您可以使用 loader.path 但前提是 Main-Class 是 PropertiesLauncher (所以这取决于您如何构建 JAR 文件).也许您需要在 Boot 插件中使用 Packaging=ZIP 重新构建 JAR(例如 文档在这里)?您不能将密钥库的路径设置为文件:"网址吗?

You can use loader.path but only if the Main-Class is PropertiesLauncher (so it depends how you built the JAR file). Maybe you need to re-build the JAR with packaging=ZIP in the Boot plugin (e.g. docs here)? Can you not set the path to the keystore as a "file:" URL?

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