JpaRepository&lt;Telefonbuch,Long&gt;类型中的findAll(Sort)方法.不适用于参数(规范<Telefonbuch>) [英] The method findAll(Sort) in the type JpaRepository&lt;Telefonbuch,Long&gt; is not applicable for the arguments (Specification&lt;Telefonbuch&gt;)

问题描述

我想实现 Specifications 并想使用 findAll(Specification spec) 方法，但总是在我插入一个规范时 Eclipse 告诉我:>

I want to implement Specifications and want to use the findAll(Specification<T> spec) method, but always when I insert an Specification Eclipse tells me:

The method findAll(Sort) in the type JpaRepository<Telefonbuch,Long> is not applicable for the arguments (Specification<Telefonbuch>)

我不想使用Sort.我交了一个规范，为什么它总是尝试使用带有 sort 的方法?

I don't want to use Sort. I hand over a specification so why does it always try to use the method with sort?

您可以在这里看到该方法是 Eclipse 的建议:https://imgur.com/a/LuF6ZGK

You can see here that the method is a suggestion by Eclipse: https://imgur.com/a/LuF6ZGK

规格:

public interface Specification<T> {
    Predicate toPredicate(Root<T> root, CriteriaQuery<?> query, CriteriaBuilder builder);
}

电话簿规格:

public static Specification<Telefonbuch> hasVorname(String vorname) {
    return (root, query, cb) -> {
        return cb.equal(root.get(Telefonbuch_.vorname), "%"+vorname.toLowerCase()+"%");
    };
}

TelefonbuchRepository:

TelefonbuchRepository:

public interface TelefonbuchRepository extends JpaRepository<Telefonbuch, Long>, JpaSpecificationExecutor<Telefonbuch> {

搜索控制器:

public void search(String vorname, String nachname, String telefonnummer, String handynummer) {  
    if (!vorname.isEmpty()) {   
        List<Telefonbuch> list = telefonbuchRepository.findAll(TelefonbuchSpecifications.hasVorname(vorname));
    }

在这里

List<Telefonbuch> list = telefonbuchRepository.findAll(TelefonbuchSpecifications.hasVorname(vorname));
        }

它告诉我:JpaRepository类型中的findAll(Sort)方法不适用于参数(规范)

推荐答案

您的存储库还需要实现 JpaSpecificationExecutor 以查看 findAll(Specification) 方法.

Your repository additionally needs to implement JpaSpecificationExecutor to see the findAll(Specification<T>) method.

另外，请注意，我们不建议首先扩展 JpaRepository 而是使用一个不太公开的接口 CrudRepository 或 PagingAndSortingRepository.请参阅此答案参考.

Also, note that we don't recommend to extend JpaRepository in the first place but rather use one of the less revealing interfaces CrudRepository or PagingAndSortingRepository. See this answer for reference.

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