Spring Data JPA:java.lang.NoSuchMethodException:java.util.List.<init>() [英] Spring Data JPA : java.lang.NoSuchMethodException: java.util.List.<init>()

问题描述

我正在使用 Spring Data JPA 来创建服务.我正在尝试在 JPQL 查询中使用 IN 子句.

I am using Spring Data JPA for creating services. I am trying to use IN clause in JPQL Query.

实际上我正在尝试将此 LinQ 查询转换为 JPQL

Actually I am trying to convert this LinQ query to JPQL

LinQ 查询

from rooms in EspaceDB.Rooms
                            where roomIDList.Contains(rooms.nRoomID.ToString())
                            select rooms;

java.lang.NoSuchMethodException: userAuth.User.()

这个解决方案对我不起作用.在我的所有模型类中，我都有默认构造函数.

This solution didn't work for me. In my all model classes I am having default constructor.

JPQL 查询语法

@Query("select room from Room as room where room.nRoomId In (:nRoomIdList)")    
    List<Room> recoverDeletedRoom(@Param(value = "nRoomIdList") List<Integer> nRoomIdList);

控制台

java.lang.NoSuchMethodException: java.util.List.<init>()
    at java.lang.Class.getConstructor0(Unknown Source) ~[na:1.8.0_144]
    at java.lang.Class.getDeclaredConstructor(Unknown Source) ~[na:1.8.0_144]
    at org.springframework.web.method.annotation.ModelAttributeMethodProcessor.createAttribute(ModelAttributeMethodProcessor.java:209) ~[spring-web-5.0.7.RELEASE.jar:5.0.7.RELEASE]

    at java.lang.Thread.run(Unknown Source) [na:1.8.0_144]

房间等级

@Entity
@Table(name = "room")
public class Room implements Serializable {

    private static final long serialVersionUID = 1L;

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY, generator = "room_seq_generator")
    @SequenceGenerator(name = "room_seq_generator", sequenceName = "room_seq",allocationSize=1)
    @Column(name = "nroom_id", columnDefinition="serial")   
    public Integer nRoomId;

    @Column(name = "ncampus_id")
    public Integer nCampusId;

     //....
     //....

     public Room() {
        super();
    }

房间控制器

@PutMapping("/recoverDeletedRoom")
    public List<Room> recoverRoom(List<Integer> nRoomIdList, Boolean IsActive) {
        return roomService.recoverDeletedRoom(nRoomIdList, IsActive);
    }

推荐答案

更改您的 @PutMapping 代码

@PutMapping("/recoverDeletedRoom")
public List<Room> recoverRoom(@RequestBody WrapperObject wrapperObject) {
   return roomService.recoverDeletedRoom(wrapperObject.getNRoomIdList(), getIsActive());
}

并得到放置映射体；

public class WrapperObject {

    List<Integer> nRoomIdList;
    Boolean isActive;

    //getters setters
}

这篇关于Spring Data JPA:java.lang.NoSuchMethodException:java.util.List.<init>()的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！