在此 PHP 代码中防止 SQL 注入 [英] Prevent SQL Injection In This PHP Code
问题描述
我有以下写入 PostgreSQL 数据库的函数.我需要使其免受 SQL 注入的影响,但我不知道该怎么做.
I have the following function that writes into a PostgreSQL database. I need to make it safe from SQL injection however I am not sure how to do that.
从 pg_query_params
组装的查询部分不会被注入(或者我被告知),但是组装查询的另一部分通过 PHP 的字符串连接 .
显然容易受到注射.
The part of the query assembled from pg_query_params
is safe from injection (or so I have been told) however the other part of the assembled query via PHP's string concatenation .
is apparently vulnerable to injection.
private function setItem($table, $id, $field, $itemId, $fieldValue){
$_1 = $itemId;
$_2 = $fieldValue;
$_3 = $field;
$_4 = $table;
$_5 = $id;
$parameters = array($_1, $_2);
// If the ID already exists, then update the name!
$sql = 'update ' . $_4 . ' set ' .$_3 . ' = $2 where ' . $_5 . ' = $1;';
/*$result = */pg_query_params($this->database, $sql, $parameters);
// Add ID and Name into table.
$sql = 'insert into ' . $_4 . '(' . $_5 . ',' . $_3 . ') select $1, $2 where not exists(select 1 from ' . $_4 . ' where ' . $_5 . '=$1)';
$result = pg_query_params($this->database, $sql, $parameters);
return $result;
}
如何防止 PHP 中的 SQL 注入?似乎没有解决我的担忧.
How can I prevent SQL injection in PHP? doesn't seem to address my concern.
我正在使用 PostgreSQL 并试图找到与 pg_query_params
I am using PostgreSQL and trying to find something compatible with pg_query_params
推荐答案
您可以使用 quote_ident(),然后再创建要执行的查询.你需要这样的东西:
You can ask the database to secure your table and column names, using quote_ident(), before you create the query you want to execute. You need something like this:
<?php
$table = 'table name'; // unsafe
$column = 'column name'; // unsafe
$result = pg_query_params($connection,
'SELECT quote_ident(CAST($1 AS text)), quote_ident(CAST($2 AS text));',
array($table, $column)
);
$table = pg_fetch_result($result, 0, 0); // safe
$column = pg_fetch_result($result, 0, 1); // safe
$sql = 'INSERT INTO '.$table.'('.$column.') VALUES($1);';
echo $sql;
$result = pg_query_params($connection, $sql, array('foo'));
?>
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