SQL炼金术不区分大小写的排序顺序 [英] SQL alchemy case insensitive sort order

问题描述

我正在尝试使用 sql alchemy 对 sqlite 数据库中的特定列实现升序排序，我遇到的问题是我要排序的列具有大写和小写数据，因此排序顺序没有正常工作.

Hi Im trying to achieve a ascending sort order for particular columns in a sqlite database using sql alchemy, the issue im having is that the column I want to sort on has upper and lower case data and thus the sort order doesn't work correctly.

然后我发现了 func.lower 并尝试将其合并到查询中，但它要么出错要么就是不起作用，有人可以给我一个工作示例，说明如何使用 sql alchemy 进行不区分大小写的升序排序.

I then found out about func.lower and tried to incorporate this into the query but it either errors or just doesn't work, can somebody give me a working example of how to do a case insensitive ascending sort order using sql alchemy.

以下是我目前所拥有的(抛出错误):-

below is what I have so far (throws error):-

session.query(ResultsDBHistory).order_by(func.lower(asc(history_sort_order_column))).all()

蟒蛇 2.6.6sql 炼金术 0.7.10

python 2.6.6 sql alchemy 0.7.10

推荐答案

您需要反转函数的顺序:

session.query(ResultsDBHistory).order_by(asc(func.lower(history_sort_order_column))).all()

所以先，然后声明升序.

或者，将排序规则更改为 NOCASE:

Alternatively, change the collation to NOCASE:

from sqlalchemy.sql import collate

session.query(ResultsDBHistory).order_by(asc(collate(history_sort_order_column, 'NOCASE'))).all()

无论如何，这可以说是一个更好的主意.

which arguably is a better idea anyway.

我不认为ASC是必需的，不使用它会在一定程度上简化您的代码:

I don't think the ASC is required, leaving that off simplifies your code somewhat:

from sqlalchemy.sql import collate

session.query(ResultsDBHistory).order_by(collate(history_sort_order_column, 'NOCASE')).all()

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